
We know that, in ∆ABC,
∠A+∠B+∠C = 180°
But the triangle is right angled at C
ie., ∠C = 90°
Therefore, ∠A+∠B+ 90° = 180°
⇒ ∠A + ∠B = 90°
Therefore, <u>cos(A + B) = cos 90º = 0</u>
Answer: I can answer in a bit
I think you have to roll it um untill I roll a 4 I'm srry
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I need more to answer
Answer:
N= 8
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Answer:
3520
Step-by-step explanation:
33-11=22
40 times 22=880
880 times 4=3520
Answer:

Step-by-step explanation:
