Answer: The answer is the 3rd one
Answer:
The approximate distance is 15416 miles....
Step-by-step explanation:
We have given:
A satellite is 19,000 miles from the horizon of earth.
The radius is 4,000 miles.
Lets say that BC =x
AO = OB = 4,000 miles
AC = 19,000 miles
The tangent from the external point forms right angle with the radius of the circle.
So in ΔABC
(OC)² = (AC)²+(OA)²
where OC = x+4000
AC = 19,000
OA = 4000
Therefore,
(x+4000)² = (19,000)² +(4,000)²
Take square root at both sides:
√(x+4000)² = √(19,000)² +(4,000)²
x+4000 =√361000000+16000000
x+4000 = √377000000
x+4000 = 19416.48
x= 19416.48 - 4000
x = 15416.48
Therefore the approximate distance is 15416 miles....
Answer:
<h2>D: y= -(1/3)x -3</h2>
Step-by-step explanation:
x-2y = -2
x-2(-3x+8)=-2
mutiply the bracket by -2
(-2)(-3x)=6x
(-2)(8)=-16
x+6x-16=-2
7x-16=-2
move -16 to the other side
sign changes from -16 to +16
7x-16+16=-2+16
7x= -2+16
7x= 14
divide both sides by 7
7x/7=14/7
x=2
Find y by using the substitution method
y=-3x+8
y=-3(2)+8
-6+8
=2
Answer:(2,2)
