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2 years ago

The radius of a circle is 10 cm. What is the volume?

2 answers:

3 0

The 3-dimensional shape of a circle is a sphere. In order to solve the volume (v) of a sphere from the radius or diameter of any circumscribed circle within is as follows:
v = 4/3 × pi × r^3, where pi roughly = 3.14
v = 4/3 × 3.14 × (10cm)^3
v = 1.33 × 3.14 × 1000cm^3
v = 4,188.56 cm^3 (cubic cm)
v = 4,189 cm^3 (rounded up)

dmitriy555 [2]2 years ago

3 0

I believe the answer is 4,188.79

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Polynomials are written with the exponents of the terms in _____ order.

lozanna [386]

Answer: "...in descending order."

There you go.

6 0

3 years ago

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FULL POINTS AND BRAINLIEST

HACTEHA [7]

Answer:

2) y = 0.95x + 4

3) slope: height increases by 0.95 units as x increases by 1 unit

intercept: initial height

Step-by-step explanation:

Using (20,23) and (40,42)

Slope: (42 - 23)/(40 - 20)

0.95

y = 0.95x+ c

23 = 0.95(20) + c

c = 4

y = 0.95x + 4

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3 years ago

Triangle RST is shown. What is the y-coordinate of the final image of vertex T after the triangle is reflected over the x-axis f

gavmur [86]

Answer:

R¹(-7, -3) , S¹(-2, -1), T¹(-5, 4)

Step-by-step explanation:

Step(i):-

From the graph, the points are R(-4,5), S(1,3),T(-2,-2)

First, the points are reflected over the x-axis then transform in to

(x,y)→(x,-y)

R(-4,5)→R¹(-4,-5)

S(1,3)→S¹(1,-3)

T(-2,-2)→T¹(-2,2)

Step(ii):-

Next, The points are shifted to 3 units left then the transform

(x,y)→ (x -3 ,y)

R¹(-4,-5)→ R¹(-4-3, -5) → R¹(-7, -5)

S¹(1,-3) → S¹(1-3, -3) → S¹(-2, -3)

T¹(-2,2) → T¹(-2-3, 2)→ T¹(-5, 2)

Step(iii):-

Now again the points are shifted to '2' units up then transform to

(x,y) )→ (x ,y+2)

R¹(-7, -5+2) → R¹(-7, -3)

S¹(-2, -3+2) → S¹(-2, -1)

T¹(-5, 2+2) → T¹(-5, 4)

4 0

3 years ago

What are three ratios that are equivalent to 6/7

Tasya [4]

14 and 21 and 18

is three of them

5 0

2 years ago

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PLEASE help. The problem is to find the indicated sum.

alukav5142 [94]

The indicated sum is 350. The answer is 350 because the E or sigma is making you do (6j+2) ten times. Every time you do 6j+2 you start with j as 1 and add a 1 to j for every time you add. For example, [6(1)+2]+[6(2)+2]+[6(3)+2]...[6(10)+2].

Hope this helps.

8 0

3 years ago