All categories

3 years ago

Y=586x=1000 1172x+2y=2000

Mathematics

2 answers:

r-ruslan [8.4K]3 years ago

5 0

Answer:

klmqe

Step-by-step explanation:

777dan777 [17]3 years ago

3 0

Answer:

The answer is that this equation is false it does not equal. 688792≠2000

Step-by-step explanation:

If yu plug in the values of x and y you will get 688792 and that is not equal to 2000.

You might be interested in

Please help! BRAINLIEST to correct answer!

Nostrana [21]

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

$2 {x}^{3} + 2 {x}^{2} - 40x =$

$2x( {x}^{2} + x - 20) =$

$2x(x - 4)(x + 5)$

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

The correct answer is (( a )) .

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

8 0

3 years ago

Read 2 more answers

businessText message users receive or send an average of 62.7 text messages per day. How many text messages does a text message

KiRa [710]

Answer:

(a) The probability that a text message user receives or sends three messages per hour is 0.2180.

(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let X = number of text messages receive or send in an hour.

The random variable X follows a Poisson distribution with parameter λ.

It is provided that users receive or send 62.7 text messages in 24 hours.

Then the average number of text messages received or sent in an hour is: $\lambda=\frac{62.7}{24}= 2.6125$ .

The probability of a random variable can be computed using the formula:

$P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0, 1, 2, 3, ...$

(a)

Compute the probability that a text message user receives or sends three messages per hour as follows:

$P(X=3)=\frac{e^{-2.6125}(2.6125)^{3}}{3!} =0.21798\approx0.2180$

Thus, the probability that a text message user receives or sends three messages per hour is 0.2180.

(b)

Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

= 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

$=1-\frac{e^{-2.6125}(2.6125)^{0}}{0!}-\frac{e^{-2.6125}(2.6125)^{1}}{1!}-\frac{e^{-2.6125}(2.6125)^{2}}{2!}-\frac{e^{-2.6125}(2.6125)^{3}}{3!}\\=1-0.0734-0.1916-0.2503-0.2180\\=0.2667$

Thus, the probability that a text message user receives or sends more than three messages per hour is 0.2667.

6 0

3 years ago

Dorothy's dietary intake for one day consisted of 250 grams of carbohydrate, 60 grams of protein, and 40 grams of fat. What perc

tester [92]

Answer:

$\%Percent = 17.14\%$

Step-by-step explanation:

Given

$Carbohydrate = 250\ g$

$Protein = 60\ g$

$Fat = 40\ g$

Required

Determine the percentage of protein

First, we need to calculate the total:

$Total = Carbohydrate + Protein + Fats$

$Total = 250\ g + 60\ g + 40\ g$

$Total = 350\ g$

Percentage of protein is calculated as thus:

$\%Percent = \frac{Protein * 100\%}{Total}$

$\%Percent = \frac{60 * 100\%}{350}$

$\%Percent = \frac{6000\%}{350}$

$\%Percent = 17.14\%$

4 0

3 years ago

Find the 20th term of the arithmetic sequence 15,9,3,-3

kati45 [8]

Answer:

-99

Step-by-step explanation:

$a = 15 \\ d = - 6 \\ {n}^{th} term = a + (n + 1)d = 15 + (n - 1)( - 6) \\ {20}^{th} term =15 + (20 - 1)( - 6) = 15 - 114 = - 99$

3 0

3 years ago

Please help me with this

podryga [215]

Answer:

1 7

-120 -22

Step-by-step explanation:

you need to do top left top right bottom left bottom. in order to move x to the other side you need to subtract then divide by the negative.

4 0

3 years ago