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Natalija [7]
3 years ago
13

De quelle atome dérive le néon svp

Chemistry
1 answer:
Zarrin [17]3 years ago
7 0

Answer:

sorry

Explanation:

sorry I don't know language

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Answer: The answer would be C. Please give me a thanks :) bye!

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4 years ago
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The current day periodic table is organized by
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Answer:

Dmitri Mendeleev

Explanation:

Dmitri Mendeleev published the first recognizable periodic table in 1869, developed mainly to illustrate periodic trends of the then-known elements. He also predicted some properties of unidentified elements that were expected to fill gaps within the table. Most of his forecasts proved to be correct

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3 years ago
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A system is composed of 7.14 grams of Ne gas at 298 K and 1 atm. When 2025 joules of heat are added to the system at constant pr
dlinn [17]

Answer:

(a) 1 atm, 8.72 L and 298 K respectively.

(b) 1 atm, 16.72 L and 573.35 K respectively.

(c) \Delta U=1215J

Explanation:

Hello,

(a) In this case, considering that neon could be considered as an ideal gas, we can compute its volume as follows:

PV=nRT\\\\V=\frac{nRT}{P}=\frac{7.14g*\frac{1mol}{20g}0.082\frac{atm*L}{mol*K}*298K}{1atm}\\  \\V=8.72L

Thus, initial conditions of pressure volume and temperature are 1 atm, 8.72 L and 298 K respectively.

(b) Since the process was carried out at constant pressure, the work is defined as:

W=P(V_2-V_1)

Thus, the final volume is:

V_2=\frac{W}{P} +V_1=\frac{810Pa*m^3}{1atm*\frac{101325Pa}{1atm} } *\frac{1000L}{1m^3}+8.72L\\ \\V_2=16.72L

And the final temperature is computed by considering the pressure-constant specific heat of neon (1.03 J/g*K) and the added heat:

Q=mCp(T_2-T_1)\\\\T_2=\frac{Q}{mCp}+T_1 =\frac{2025J}{7.14g*1.03J/(g*K)}+298K\\ \\T_2=573.35K

Therefore, final volume is 16.72 L, final pressure is also 1 atm and final temperature is 573.35 K for this expansion process.

(c) Finally, the change in the internal energy is computed via the first law of thermodynamics:

Q-W=\Delta U\\\\\Delta U=2025J-810J\\\\\Delta U=1215J

Best regards.

8 0
4 years ago
A glucose molocule is the
Margaret [11]

Answer: Glucose (C6H12O6) is a hexose -- a monosaccharide containing six carbon atoms. Glucose is an aldehyde (contains a -CHO group). Five of the carbons plus an oxygen atom form a loop called a "pyranose ring", the most stable form for six-carbon aldoses.

Explanation:.

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How many carbon atoms are there in a 1.3-carat diamond? diamonds are a form of pure carbon. (1 carat?
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How many carbon atoms are there in a 1.3-carat diamond? Answer: 1.3 x 10^22 C atoms...
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0.0216 * 6.022*10^23 = 1.3*10^22 C atoms

Hope this helps! :)
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3 years ago
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