Question

For the reaction co(g)+2h2(g)<->ch3oh(g) at 700. k, equilibrium concentrations are [h2] = 0.072 m, [co] = 0.020 m, and [ch3oh] = 0.030 m. calculate k

Answer 1

The balanced equation for the reaction is
CO(g) + 2H₂(g) ⇄ CH₃OH(g)

Since given concentrations are at equilibrium state, the expression for the equilibrium constant, k can be written as
   k = [CH₃OH(g)] / [CO(g)] [H₂(g) ]²

By substitution,
   k = 0.030 M / 0.020 M x (0.072 M)²
   k = 289.35 M⁻²