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ozzi
3 years ago
7

For the reaction co(g)+2h2(g)<->ch3oh(g) at 700. k, equilibrium concentrations are [h2] = 0.072 m, [co] = 0.020 m, and [ch

3oh] = 0.030 m. calculate k
Chemistry
1 answer:
SVETLANKA909090 [29]3 years ago
6 0
The balanced equation for the reaction is
CO(g) + 2H₂(g) ⇄ CH₃<span>OH(g)

Since given concentrations are at equilibrium state, the expression for the equilibrium constant, k can be written as
   k = [</span>CH₃OH(g)] / [CO(g)] [H₂(g) ]²

By substitution,
   k = 0.030 M / 0.020 M x (<span>0.072 M</span>)²
   k = 289.35 M⁻²
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