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Alexandra [31]
3 years ago
12

The current day periodic table is organized by

Chemistry
2 answers:
Elanso [62]3 years ago
8 0

Answer:

Dmitri Mendeleev

Explanation:

Dmitri Mendeleev published the first recognizable periodic table in 1869, developed mainly to illustrate periodic trends of the then-known elements. He also predicted some properties of unidentified elements that were expected to fill gaps within the table. Most of his forecasts proved to be correct

Sergeeva-Olga [200]3 years ago
6 0

Answer:

Mendeleev periodic table

Explanation:

In 1869, just five years after John Newlands put forward his

Law of Octaves, a Russian chemist called Dmitri Mendeleev

published a periodic table. Mendeleev also arranged the

elements known at the time in order of relative atomic mass

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Which of these reactions are redox reactions and why?
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It will be number 1.
NO loses oxygen ie its being reduced to N2
NH3 gains oxygen atom ie its being oxidised to H2O
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3 years ago
Which statement describes the masses of the particles that make up an atom?
Novay_Z [31]
The mass of the atom is equal to the sum of the number of protons and the number of neutrons. In a neutral atom, the number of protons is equal to the number of electrons.  The atomic number meanwhile of an atom is equal to the number of protons of the atom.
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The chemical symbol for a calcium ion is ca2 . what does the 2 symbolize
Blababa [14]
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8 0
3 years ago
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poizon [28]
Barium Chloride
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4 0
3 years ago
A compound made of two elements, iridium (Ir) and oxygen (O), was produced in a lab by heating iridium while exposed to air. The
natima [27]
1) Compund Ir (x) O(y)

2) Mass of iridium = mass of crucible and iridium - mass of crucible = 39.52 g - 38.26 g = 1.26 g

3) Mass of iridium oxide = mass of crucible and iridium oxide - mass of crucible = 39.73g - 38.26g = 1.47g

4) Mass of oxygen = mass of iridum oxide - mass of iridium = 1.47g - 1.26g = 0.21g

5) Convert grams to moles

moles of iridium = mass of iridium / molar mass of iridium = 1.26 g / 192.17 g/mol = 0.00656 moles

moles of oxygen = mass of oxygen / molar mass of oxygen = 0.21 g / 15.999 g/mol = 0.0131

6) Find the proportion of moles

Divide by the least of the number of moles, i.e. 0.00656

Ir: 0.00656 / 0.00656 = 1

O: 0.0131 / 0.00656 = 2

=> Empirical formula = Ir O2 (where 2 is the superscript for O)

Answer: Ir O2
5 0
3 years ago
Read 2 more answers
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