The value of the x is 2 and the value of the y is 0 in the system of equation 3y=x-2, y=-2x+4.
<h3>What is a linear equation?</h3>
It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.
If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.
We have a system of the equation:
3y=x-2 ..(1)
y=-2x+4 ...(2)
From the equation (2) take the value of y and plug in the equation (1)
3(-2x+4) = x -2
-6x + 12 = x - 2
7x = 14
x = 14/7
x = 2
Plug this value in the equation (2)
y = -2(2) + 4
y = 0
Thus, the value of the x is 2 and the value of the y is 0 in the system of equation 3y=x-2, y=-2x+4.
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Answer:
For this case we have the following fraction:
To find the common denominator, what we must do is rewrite the fraction.
For this, we subtract fractions in the numerator and the sum of fractions in the denominator.
We have then:
We observe that the common denominator is given by the product:
Answer:
the common denominator is:
D)ab
Step-by-step explanation:
The answer would be b=a/c
Can you give more information about this question?

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No solution in real numbers.