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exis [7]
3 years ago
14

True or false? All quadrilaterals are also rhombuses.

Mathematics
2 answers:
Molodets [167]3 years ago
4 0

Answer:

It's false

All quadrilaterals are also rhombus, <u>False</u>

zvonat [6]3 years ago
3 0

Answer:

The answer is true. A rhombus is a quadrilateral that has four sides that are equal. This definition can also be applied for a square.

Step-by-step explanation:

You might be interested in
G(x)=x^3+5x h(x) =x+3 find (g+h)(x)
exis [7]

(g+h)(x) = x^3+6x+3

Step-by-step explanation:

The operations on functions can be performed as they are performed on polynomials

The addition of functions is used in the given question

Given

g(x)=x^3+5x\\h(x)=x+3

We have to find:

(g+h)(x)=g(x)+h(x)\\=x^3+5x+x+3\\=x^3+6x+3

So,

(g+h)(x) = x^3+6x+3

Keywords: Functions, operations on functions

Learn more about functions at:

  • brainly.com/question/4892332
  • brainly.com/question/4924817

#LearnwithBrainly

7 0
3 years ago
Describe the possible values for x and y when ∣x − y ∣ &gt; 0. What does it mean when ∣x − y ∣ = 0? Can ∣x − y ∣ &lt; 0? Explain
Vilka [71]
The possible values for | x-y | > 0 is any number above 0. x must be greater than y. When | x-y | = 0, That means that x and y are equal to each other. | x-y | can not be less than 0, but it can equal 0.

Hope that this helped!
4 0
3 years ago
Find the measure of exterior 1.
svetlana [45]
The answer would be 90.
8 0
3 years ago
Read 2 more answers
***WORTH 40 POINTS*** [−3−4x≤21]
Ksenya-84 [330]

Answer:

the croccect amswer is A

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Fred and Frank play a game. Fred picks an even number X and asks Frank to add all even numbers between 0 and X (inclusive) as fa
TiliK225 [7]

Answer:

The even numbers between 0 and X represents an arithmetic sequence with a common difference of 2

The rule of arithmetic sequence = a + d(n - 1)

Where a is the first term and n is the number of terms

So, for the even numbers between 0 and X

The first term = a = 0

d = 2

So, we need to find n at the last term which is X

∴ X = 0 + 2 ( n -1 )

∴ n - 1 = X/2

∴ n = X/2 + 1

The sum of the arithmetic sequence = (n/2) × (2a + (n−1)d)

Substitute with a and d and X

So, the sum = (n/2) * (2*0 + (n−1)*2)

                   = (n/2) * ((n−1)*2)

                   = n(n-1)

                   = (X/2 + 1) * (X/2)

                   = X/2 by (X/2 + 1)

So, The quick way to add all even numbers between 0 and X always works.

8 0
3 years ago
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