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3 years ago

What is the slope-intercept form of a linear equation that passes through (-3,7) and is parallel to the equation y=2x+5

Mathematics

1 answer:

Misha Larkins [42]3 years ago

4 0

Answer:

The answer to your question is y = 2x + 13

Step-by-step explanation:

Data

Point ( -3, 7)

Parallel to y = 2x + 5

Process

1.- Find the slope of the new line

If two lines are parallel, they have the same slope.

The slope of the line given is "2", so the new line has the same slope.

2.- Substitute the date in the formula

y - y₁ = m(x - x₁)

y - 7 = 2(x + 3)

Expland

y - 7 = 2x + 6

Simplify

y = 2x + 6 + 7

y = 2x + 13

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3,240 / 9= 360\

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3 years ago

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What is 3x3x4/45 does anyone know the answer

MariettaO [177]

Answer:

4/5 or 0.8

Step-by-step explanation:

3*3*4/45

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4 years ago

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A line passes through the points (3,5) and (2,0) what is the slope of the line?

Veronika [31]

Answer:

Step-by-step explanation:

slope = (difference in y)/(difference in x)

subtract the y-coordinates: 5 - 0 = 5

subtract the x-coordinates in the same order: 3 - 2 = 1

Divide the difference in y by the difference in x.

slope = 5/1 = 5

4 0

3 years ago

PLEASE HELP ASAP

maria [59]

Answer:

First option: $3x^2-5x=-8$

Second option: $2x^2=6x-5$

Fourth option: $-x^2-10x=34$

Step-by-step explanation:

Rewrite each equation in the form $ax^2+bx+c=0$ and then use the Discriminant formula for each equation. This is:

$D=b^2-4ac$

1) For $3x^2-5x=-8$ :

$3x^2-5x+8=0$

Then:

$D=(-5)^2-4(3)(8)=-71$

Since $D$ this equation has no real solutions, but has two complex solutions.

2) For $2x^2=6x-5$ :

$2x^2-6x+5=0$

Then:

$D=(-6)^2-4(2)(5)=-4$

Since $D$ this equation has no real solutions, but has two complex solutions.

3) For $12x=9x^2+4$ :

$9x^2-12x+4=0$

Then:

$D=(-12)^2-4(9)(4)=0$

Since $D=0$ this equation has one real solution.

4) For $-x^2-10x=34$ :

$-x^2-10x-34=0$

Then:

$D=(-10)^2-4(-1)(-34)=-36$

Since $D$ , this equation has no real solutions, but has two complex solutions.

3 0

3 years ago

Which proportion can be used to show that the slope of AC is equal to the slope of CE?

Gnesinka [82]

Slope is given by the expression:

$m=\frac{y_2-y_1}{x_2-x_1}$

We can equal both slopes of mAC and mCE

$\begin{gathered} \frac{3-6}{-1-(-3)}=\frac{-3-3}{3-(-1)} \\ \\ \frac{-3}{2}=-\frac{6}{4} \\ -\frac{3}{2}=-\frac{3}{2} \end{gathered}$

Answer is B.

5 0

1 year ago