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2 years ago

7

a house is assessed for $220,00. If a tax rate is $3 per $100, find the property tax. Use the following formula to answer the qu

estion: property tax = assessed value/$100 × rate (amount)

1 answer:

GalinKa [24]2 years ago

5 0

$6,600

Just divide $220,000 by $100 like so- 220,000/100=2,200 now just multiply 2,200 by 3 like 2,200(3)= 6,600

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3^4+4.5= Input whole number

Nina [5.8K]

<h2>86</h2>

Step-by-step explanation:

<h3>(3 × 3 × 3 × 3) + 4.5</h3><h3>81 + 4.5</h3><h3>85.5</h3>

<h2>MARK ME AS BRAINLIST</h2><h2>PLZ FOLLOW ME</h2>

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2 years ago

Read 2 more answers

The equation ý-x+4 is graphed below. Which equation would intersect this line at the point (4, 6)?

mel-nik [20]

Answer:

Your answer would be A. y=6!

Step-by-step explanation:

Have a nice day! :)

7 0

3 years ago

Give the following equations determine if the lines are parallel perpendicular or neither

GaryK [48]

In order to determine whether the equations are parallel, perpendicular, or neither, let's simply each equation into a slope-intercept form or basically, solve for y.

Let's start with the first equation.

$\frac{6x-5y}{2}=x+1$

Cross multiply both sides of the equation.

$6x-5y=2(x+1)$ $6x-5y=2x+2$

Subtract 6x on both sides of the equation.

$6x-5y-6x=2x+2-6x$ $-5y=-4x+2$

Divide both sides of the equation by -5.

$-\frac{5y}{-5}=\frac{-4x}{-5}+\frac{2}{-5}$ $y=\frac{4}{5}x-\frac{2}{5}$

Therefore, the slope of the first equation is 4/5.

Let's now simplify the second equation.

$-4y-x=4x+5$

Add x on both sides of the equation.

$-4y-x+x=4x+5+x$ $-4y=5x+5$

Divide both sides of the equation by -4.

$\frac{-4y}{-4}=\frac{5x}{-4}+\frac{5}{-4}$ $y=-\frac{5}{4}x-\frac{5}{4}$

Therefore, the slope of the second equation is -5/4.

Since the slope of each equation is the negative reciprocal of each other, then the graph of the two equations is perpendicular to each other.

5 0

1 year ago

What is the simple quotient for 32 divide by 8/5

Softa [21]

Answer:

20

Step-by-step explanation:

32/1 / 8/5= 32/1 x 5/8= 160/8=20

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3 years ago

Write a paragraph comparing the two classes' semester grades. Be sure to compare the extremes, the quartiles, the medians, and t

Gnom [1K]

Answer:

Second class have higher marks and greater spread.

Step-by-step explanation:

First box plot represents class first. From the first box plot, we get

$\text{Minimum value }= 53,Q_1=62,Median=80,Q_3=86,\text{Maximum value }= 89$

$Range=Maximum-Minimum=89-53=36$

$IQR=Q_3-Q-1=86-62=24$

Second box plot represents class second. From the second box plot, we get

$\text{Minimum value }= 56,Q_1=62,Median=74,Q_3=89,\text{Maximum value }= 96$

$Range=Maximum-Minimum=96-56=40$

$IQR=Q_3-Q-1=89-62=27$

First class has greater minimum value, first quartile of both classes are same, second class has greater median, first class has greater third quartile and first class has greater maximum value. It means second class have higher marks but class first have less variation.

Second class has greater range and greater inter quartile range. It means data of second class has greater spread.

Therefore, second class have higher marks and greater spread.

3 0

2 years ago