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Tcecarenko [31]
3 years ago
11

An investment banker deposited $50,000 in an account earning a nominal 6% per year compounded continuously. How much was in the

account at the end of three years
Mathematics
1 answer:
Orlov [11]3 years ago
5 0

Answer:

The amount in the account at the end of three years will be $59,861.

Step-by-step explanation:

The formula to compute the amount at the end of <em>t</em> years, compounded continuously is:

A=P\times e^{t\times i}

Here,

A = Amount at the end

P = Principal amount

i = interest rate

t = number of years.

It is provided that:

P = $50,000

i = 6%

t = 3 years

Compute the amount in the account at the end of three years as follows:

A=P\times e^{t\times i}

   =50000\times e^{(3\times 0.06)}\\=50000\times 1.19722\\=59861

Thus, the amount in the account at the end of three years will be $59,861.

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. How many solutions does this system of equations have?<br> y = 4x - 2.<br> y = 4x +5 *
defon

Answer:

No solutions

Step-by-step explanation:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

3 0
2 years ago
Ritchie got a job at the movie theater. On the first day, he sold 5 adult tickets and 7 children tickets for a total of 104. On
g100num [7]

Answer:

  • adult: $11
  • children: $7

Step-by-step explanation:

The sales on the two days can be expressed using equations that can be solved for ticket prices.

<h3>Setup</h3>

Let x and y represent the prices of adult and children's tickets, respectively. Then the sales revenue for the two days can be expressed in the equations ...

  • 5x +7y = 104
  • 7x +3y = 98

<h3>Solution</h3>

One of the easiest solution methods is to use a graphing calculator. The first attachment shows the prices are $11 for an adult ticket; $7 for children tickets.

Using the matrix functions of a calculator, the augmented matrix of the equation coefficients can be reduced to row-echelon form. This, too, shows the solution to be (adult price, children price) = ($11, $7). See the second attachment. (The solution is the right-most column of the reduced matrix.)

Yet another solution method can use the coefficients from the equations written in general form:

  • 5x +7y -104 = 0
  • 7x +3y -98 = 0

In this form, we define three products of "cross multiplication":

  Δ1 = (5)(3) -(7)(7) = -34

  Δ2 = (7)(-98) -(3)(-104) = -374

  Δ3 = (-104)(7) -(-98)(5) = -238

Using those, we find the variable values to be ...

  x = Δ2/Δ1 = -374/-34 = 11

  y = Δ3/Δ1 = -238/-34 = 7

(adult price, children price) = ($11, $7)

__

You can read more about the cross-multiplication method here:

brainly.com/question/26397343

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1 year ago
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Solve the following quadratic equation. *<br> x^2+12x-45=0
liq [111]

Answer:

9 over 5

Step-by-step explanation:

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3 years ago
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Write an equation for: The length of a rectangle is 6 times the width. use the variables l and w
Fittoniya [83]
L=6w would be an equation for the length of a rectangle that is 6 times the width
8 0
3 years ago
Reuben learned in art class that a mosaic is made by arranging small pieces of colored material such as glass or tile to create
anastassius [24]

Pattern is the rule that guides the formation of a set.

  • <em>The sequence of the first five mosaics is 5, 8, 11, 14, 17</em>
  • <em>The sequence is arithmetic</em>
  • <em>There are 32 tiles in the tenth mosaic.</em>

From the given design, the number of tiles used is:

T_1 = 5

T_2 = 8

T_3 = 11

<u />

<u>(a) The first five</u>

Notice that the difference in the number of tiles of successive mosaic is 3.

This means that:

T_4 = T_3 + 3 = 11 +3 = 14

T_5 = T_4 + 3 = 14 +3 = 17

So, the sequence of the first five mosaics is 5, 8, 11, 14, 17

<u>(b) The type of sequence</u>

The sequence is arithmetic

This is so, because the difference in the number of tiles of successive mosaic is 3.

This difference is called the common difference

<u>(c) The number of tiles in the tenth mosaic</u>

The nth term of an arithmetic sequence is:

T_n = T_1 + (n - 1) \times d

In this case:

T_1 = 5

d =3

n = 10

So, we have:

T_{10} = 5 + (10 - 1) \times 3

T_{10} = 5 + 9 \times 3

T_{10} = 5 + 27

T_{10} = 32

There are 32 tiles in the tenth mosaic.

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