1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Pavlova-9 [17]
3 years ago
11

Help me please and thank yall !!!!!

Mathematics
1 answer:
Artyom0805 [142]3 years ago
6 0

Answer:

Step-by-step explanation:

So technically all you need to do is what number is in front of it and what number is in back of it.

You might be interested in
Below are two parallel lines with a third line intersecting them.
Allushta [10]
180-48= 132 ( I think)
8 0
2 years ago
A map of a park says its scale is 1 to 100. What does that mean?
Alex777 [14]

A scale is a term that refers to the <em>representative fraction</em> for comparing the <u>original</u> length and <u>image</u> length of a given <u>object</u>. It means implies that every 1 unit on the <u>drawing</u> is equal to <u>100</u> units on the <u>park</u>.

A <em>scale</em> is a term that can be referred to as the <em>representative fraction</em> that compares the <u>original</u> length and <u>image</u> length of a given <em>object</em>. Types of <u>scale</u> include enlarged scale, reduced scale, and real scale.

  • Enlarged scale is a <u>scale</u> that is used when the <u>size</u> of a given <em>object</em> is to be <em>increased</em>.
  • <em>Reduced scale</em> is used when the <u>size</u> of a given <u>object</u> is to be <em>decreased</em>.
  • <u>Real scale</u> implies the <em>exact size</em> of a given <u>object</u>.

<u>Scale</u> can be expressed as;

Scale = \frac{length on drawing}{original length}

Thus a <em>scale</em> has no unit.

Therefore, the given question <em>implies</em> that every 1 unit on the <u>drawing</u> is equal to 100 units on the <u>original</u> park. Thus it is a <em>reduced scale</em>.

For more clarifications on a scale drawing, visit: brainly.com/question/23209981

#SPJ1

6 0
1 year ago
Find the inverse.. ASAP
Evgen [1.6K]
Answer :
F-1(x)=-x/4-7/4


This is right
Go get help to sum sites!!!!!

8 0
2 years ago
Solve the following systems of equations using the matrix method: a. 3x1 + 2x2 + 4x3 = 5 2x1 + 5x2 + 3x3 = 17 7x1 + 2x2 + 2x3 =
lara [203]

Answer:

a. The solutions are

\left[\begin{array}{c}x_1&x_2&x_3\\\end{array}\right]=\begin{pmatrix}\frac{11}{13}\\ \frac{50}{13}\\ -\frac{17}{13}\end{pmatrix}

b. The solutions are

\left[\begin{array}{c}x&y&z\\\end{array}\right]=\begin{pmatrix}\frac{54}{235}\\ \frac{6}{47}\\ \frac{24}{235}\end{pmatrix}

c. The solutions are

\left[\begin{array}{c}x_1&x_2&x_3&x_4\\\end{array}\right]=\begin{pmatrix}\frac{22}{9}\\ \frac{164}{9}\\ \frac{139}{9}\\ -\frac{37}{3}\end{pmatrix}

Step-by-step explanation:

Solving a system of linear equations using matrix method, we may define a system of equations with the same number of equations as variables as:

A\cdot X=B

where X is the matrix representing the variables of the system,  B is the matrix representing the constants, and A is the coefficient matrix.

Then the solution is this:

X=A^{-1}B

a. Given the system:

3x_1 + 2x_2 + 4x_3 = 5 \\2x_1 + 5x_2 + 3x_3 = 17 \\7x_1 + 2x_2 + 2x_3 = 11

The coefficient matrix is:

A=\left[\begin{array}{ccc}3&2&4\\2&5&3\\7&2&2\end{array}\right]

The variable matrix is:

X=\left[\begin{array}{c}x_1&x_2&x_3\\\end{array}\right]

The constant matrix is:

B=\left[\begin{array}{c}5&17&11\\\end{array}\right]

First, we need to find the inverse of the A matrix. To find the inverse matrix, augment it with the identity matrix and perform row operations trying to make the identity matrix to the left. Then to the right will be inverse matrix.

So, augment the matrix with identity matrix:

\left[ \begin{array}{ccc|ccc}3&2&4&1&0&0 \\\\ 2&5&3&0&1&0 \\\\ 7&2&2&0&0&1\end{array}\right]

This matrix can be transformed by a sequence of elementary row operations to the matrix

\left[ \begin{array}{ccc|ccc}1&0&0&- \frac{2}{39}&- \frac{2}{39}&\frac{7}{39} \\\\ 0&1&0&- \frac{17}{78}&\frac{11}{39}&\frac{1}{78} \\\\ 0&0&1&\frac{31}{78}&- \frac{4}{39}&- \frac{11}{78}\end{array}\right]

And the inverse of the A matrix is

A^{-1}=\left[ \begin{array}{ccc} - \frac{2}{39} & - \frac{2}{39} & \frac{7}{39} \\\\ - \frac{17}{78} & \frac{11}{39} & \frac{1}{78} \\\\ \frac{31}{78} & - \frac{4}{39} & - \frac{11}{78} \end{array} \right]

Next, multiply A^ {-1} by B

X=A^{-1}\cdot B

\left[\begin{array}{c}x_1&x_2&x_3\\\end{array}\right]=\left[ \begin{array}{ccc} - \frac{2}{39} & - \frac{2}{39} & \frac{7}{39} \\\\ - \frac{17}{78} & \frac{11}{39} & \frac{1}{78} \\\\ \frac{31}{78} & - \frac{4}{39} & - \frac{11}{78} \end{array} \right] \cdot \left[\begin{array}{c}5&17&11\end{array}\right]

\left[\begin{array}{c}x_1&x_2&x_3\\\end{array}\right]=\begin{pmatrix}-\frac{2}{39}&-\frac{2}{39}&\frac{7}{39}\\ -\frac{17}{78}&\frac{11}{39}&\frac{1}{78}\\ \frac{31}{78}&-\frac{4}{39}&-\frac{11}{78}\end{pmatrix}\begin{pmatrix}5\\ 17\\ 11\end{pmatrix}=\begin{pmatrix}\frac{11}{13}\\ \frac{50}{13}\\ -\frac{17}{13}\end{pmatrix}

The solutions are

\left[\begin{array}{c}x_1&x_2&x_3\\\end{array}\right]=\begin{pmatrix}\frac{11}{13}\\ \frac{50}{13}\\ -\frac{17}{13}\end{pmatrix}

b. To solve this system of equations

x -y - z = 0 \\30x + 40y = 12 \\30x + 50z = 12

The coefficient matrix is:

A=\left[\begin{array}{ccc}1&-1&-1\\30&40&0\\30&0&50\end{array}\right]

The variable matrix is:

X=\left[\begin{array}{c}x&y&z\\\end{array}\right]

The constant matrix is:

B=\left[\begin{array}{c}0&12&12\\\end{array}\right]

The inverse of the A matrix is

A^{-1}=\left[ \begin{array}{ccc} \frac{20}{47} & \frac{1}{94} & \frac{2}{235} \\\\ - \frac{15}{47} & \frac{4}{235} & - \frac{3}{470} \\\\ - \frac{12}{47} & - \frac{3}{470} & \frac{7}{470} \end{array} \right]

The solutions are

\left[\begin{array}{c}x&y&z\\\end{array}\right]=\begin{pmatrix}\frac{54}{235}\\ \frac{6}{47}\\ \frac{24}{235}\end{pmatrix}

c. To solve this system of equations

4x_1 + 2x_2 + x_3 + 5x_4 = 0 \\3x_1 + x_2 + 4x_3 + 7x_4 = 1\\ 2x_1 + 3x_2 + x_3 + 6x_4 = 1 \\3x_1 + x_2 + x_3 + 3x_4 = 4\\

The coefficient matrix is:

A=\left[\begin{array}{cccc}4&2&1&5\\3&1&4&7\\2&3&1&6\\3&1&1&3\end{array}\right]

The variable matrix is:

X=\left[\begin{array}{c}x_1&x_2&x_3&x_4\\\end{array}\right]

The constant matrix is:

B=\left[\begin{array}{c}0&1&1&4\\\end{array}\right]

The inverse of the A matrix is

A^{-1}=\left[ \begin{array}{cccc} - \frac{1}{9} & - \frac{1}{9} & - \frac{1}{9} & \frac{2}{3} \\\\ - \frac{32}{9} & - \frac{5}{9} & \frac{13}{9} & \frac{13}{3} \\\\ - \frac{28}{9} & - \frac{1}{9} & \frac{8}{9} & \frac{11}{3} \\\\ \frac{7}{3} & \frac{1}{3} & - \frac{2}{3} & -3 \end{array} \right]

The solutions are

\left[\begin{array}{c}x_1&x_2&x_3&x_4\\\end{array}\right]=\begin{pmatrix}\frac{22}{9}\\ \frac{164}{9}\\ \frac{139}{9}\\ -\frac{37}{3}\end{pmatrix}

7 0
2 years ago
Read 2 more answers
Help! I just started this in school and I am still confused
Tomtit [17]
Okay, to work out the original price, all you have to do is get the sale price ($146.54) and then divide it by 1 - 0.[whatever the percentage is]. In this case, the percentage is 15%, so you do 1 - 0.15 = 0.85.

So to work out the original price, you do:
146.54 ÷ 0.85 = $172.40

The original price is $172.40. :)
3 0
3 years ago
Read 2 more answers
Other questions:
  • 2. measure of an angle that is supplementary to
    14·1 answer
  • What are the solutions of the equation x6 + 6x3 + 5 = 0? Use factoring to solve.
    10·1 answer
  • If u have 8 points how many triangles can u make with
    12·1 answer
  • Solve the proportion. x=1/3 = x/2<br><br><br> a=5<br><br> b=2<br><br> c=10<br><br> d=1
    7·1 answer
  • Which of the following is a one-to-one function?
    15·1 answer
  • Add the following fraction 2/7 + 3/7
    15·2 answers
  • Y=x +20. What is the operation represented in this relationship?
    13·2 answers
  • What is the graph of the inequality 3x+2y&gt;-5
    11·1 answer
  • WORD PROBLEM! Sally has 15 apples. She gives some of her apples to three friends. They each get the same amount. Sally now has 9
    13·2 answers
  • Drag each graph to show if the system of linear equations it represents will have no
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!