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solmaris [256]
3 years ago
14

What is the degree of f (x) = -5x it is a linear function?What is the m and b?​

Mathematics
1 answer:
IRINA_888 [86]3 years ago
3 0

Answer:

The degree is 1

It is a linear function

m = -5 and b = 0

Step-by-step explanation:

Here, we want to get the degree of the equation

As we can see, it is a linear function with the highest power of as 1

That means it is of degree 1

Comparing with the general form;

y = mx + b

m = -5

b = 0

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Walmart is selling 24 bars Gatorade for $8.44 what is the price per bottle​
Eva8 [605]

Answer:

About $0.35 per bottle.

Step-by-step explanation:

8.44 / 24 = .3516

3 0
3 years ago
Read 2 more answers
what algebraic expression must be added to the sum of 3x squared + 4x + 8 and 2x squared -6x + 3 to give 9x squared -2x - 5 as t
gregori [183]
<span>3x^2 + 4x + 8 + 2x^2 - 6x + 3 to give result as 9x^2 -2x - 5


</span>3x^2 + 4x + 8 + 2x^2 - 6x + 3 
= 5x^2 - 2x + 11

so

9x^2 -2x - 5 - (5x^2 - 2x + 11)
= 9x^2 -2x - 5 -  5x^2 +  2x - 11
= 4x^2 -16

answer

expression (4x^2 -16) must be added to the sum of (3x^2 + 4x + 8) and (2x^2 - 6x + 3) to give the result as (9x^2 - 2x - 5)
3 0
3 years ago
Convert 212 degree Fahrenheit into degree Celsius<br>I will mark them as brainlists<br>​
Simora [160]

Answer:

The answer might be 100° c

5 0
3 years ago
Find the dimensions of the open rectangular box of maximum volume that can be made from a sheet of cardboard 11 in. by 7 in. by
11111nata11111 [884]

Answer:

The dimension of the open rectangular box is 8.216\times 4.216\times 1.392.

The volume of the box is 8.217 cubic inches.

Step-by-step explanation:

Given : The open rectangular box of maximum volume that can be made from a sheet of cardboard 11 in. by 7 in. by cutting congruent squares from the corners and folding up the sides.

To find : The dimensions and the volume of the open rectangular box ?

Solution :

Let the height be 'x'.

The length of the box is '11-2x'.

The breadth of the box is '7-2x'.

The volume of the box is V=l\times b\times h

V=(11-2x)\times (7-2x)\times x

V=4x^3-36x^2+77x

Derivate w.r.t x,

V'(x)=4(3x^2)-2(36x)+77

V'(x)=12x^2-72x+77

The critical point when V'(x)=0

12x^2-72x+77=0

Solve by quadratic formula,

x=\frac{18+\sqrt{93}}{6},\frac{18-\sqrt{93}}{6}

x=4.607,1.392

Derivate again w.r.t x,

V''(x)=24x-72

Now, V''(4.607)=24(4.607)-72=38.568>0 (+ve)

V''(1.392)=24(1.392)-72=-38.592 (-ve)

So, there is maximum at x=1.392.

The length of the box is l=11-2x

l=11-2(1.392)=8.216

The breadth of the box is b=7-2x

b=7-2(1.392)=4.216

The height of the box is h=1.392.

The dimension of the open rectangular box is 8.216\times 4.216\times 1.392.

The volume of the box is V=l\times b\times h

V=8.216\times 4.216\times 1.392

V=48.217\ in.^3

The volume of the box is 8.217 cubic inches.

5 0
3 years ago
Give an example to show that subtraction does not follow the associative rule
Agata [3.3K]

(6 - 2) - 1 = 4 - 1 = 3

6 - (2 - 1) = 6 - 1 = 5

The associative rule doesn't work for subtraction because you get different results when you move the parentheses.

4 0
3 years ago
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