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Anton [14]
3 years ago
14

What is the base of a triangle with a hypotenuse of 25cm and a right angle of 18

Mathematics
1 answer:
saveliy_v [14]3 years ago
5 0
The base of the traingle is the square root of 7
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Triangle HKJ is inscribed in the circle as shown. If the triangle is a right triangle, what can you conclude about HJ?
kifflom [539]

Answer:

HJ is diameter.

Step-by-step explanation:

Given Triangle HKJ is inscribed in the circle. we have to conclude about HJ if the triangle is a right triangle.

All the three sides are chord of the circle.

As given HKJ is right angled triangle i.e∠HKJ=90° and angle subtended by diameter in the semicircle is 90° implies HJ is diameter because if the HJ moves towards the angle then the given angle becomes acute and if moves away from the angle then the angle becomes obtuse which contradict the given information.

hence, the only possibility about the line HJ is that it is a diameter.


7 0
3 years ago
Rebecca has 3 pairs of running shoes.She bought new shoelaces for each pair.How many shoelaces did she buy?
kvasek [131]

Answer: 6 shoelaces

Step-by-step explanation:

Since 1 pair of shoes has 2 shoelaces, 3 x 2 = 6

3 pairs x 2 shoelaces = 6 shoelaces

Hope this helped!

P.S. PLS give brailiest! I only have one brainliest!!

4 0
3 years ago
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Each day a bobcat drinks about 3 times as much water as a canada goose drinks. How much water can a bobcat drink in one day?
Ahat [919]
It's. I have know idea
3 0
3 years ago
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BRAINLIESTTT ASAP! PLEASE HELP ME :)
Scrat [10]

x-intercepts: (-3,0), (1,0)

work:

0 = x^2 + 2x - 3

quadratic equation: x = -2 +√(2^(2) - 4 × 1(-3)) / (2 × 1) = 1

quadratic equation: x = -2 -√(2^(2) - 4 × 1(-3)) / (2 × 1) = -3

(x,y) --) (-3,0), (1,0)

y-intercept: (0,-3)

work:

y = (0)^2 + 2(0) - 3

y = -3

(x,y) --) (0,-3)

vertex: (-1,-4)

work:

xv = -( b / (2a) )

a = 1, b = 2, c = -3

xv = -( 2 / (2×1) )

xv = -1

yv = (-1)^2 + 2(-1) - 3

yv = -4

(x,y) --) (-1,-4)

axis of symmetry: -1

work:

a = 1 in the x^(2) + 2ax + a^(2)

x^(2) + 2x + 1^(2) = (x + 1)^(2)

(x + 1)^(2) - 3 - 1^(2)

y = (x + 1)^(2) - 4

y + 4 = (x - 1)^(2)

put in standard form --) 4 × 1/4( y -( -4 ) ) = ( x -( -1) )^(2)

(h,k) = (-1,-4); p = 1/4

in parabola form expression: 4p( y - k ) = ( x - h )^(2) and is symmetric around the y-axis at -1.

4 0
3 years ago
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Help please helpppppp
devlian [24]

Answer:

i have no idea

Step-by-step explanation:

3 0
3 years ago
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