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2 years ago

What are the y and x intercepts

Mathematics

1 answer:

Degger [83]2 years ago

7 0

Answer:

y will be 3 and x will be 3 no worry it's a wrong answer

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31y+12y= combine like terms

Varvara68 [4.7K]

Answer:

43y

Step-by-step explanation:

31y+12y

combine like terms

Factor out y

y( 31+12)

y (43)

43y

3 0

3 years ago

Read 2 more answers

1 and 2 are a linear pair, and 2 and 3 are vertical angles. m 2=(5+4 y) and m 3=(6 y-25). what is m 1

poizon [28]

Vertical angles are equal to each other:
    ∠2    =    ∠3
   5 + 4y = 6y - 25
→ 30 = 2y
→    15 = y

∠2 = 5 + 4y = 5 + 4(15) = 5 + 60 = 65

linear pairs equal 180:
   ∠1 + ∠2 = 180
→ ∠1 + 65 = 180
→ ∠1 = 115

5 0

3 years ago

Kayla drives 15 miles in 20 minutes. If she drove one hour in total at the same rate,

Rudik [331]

Answer:

45 miles

Step-by-step explanation:

first divide miles/minutes: 15 / 20 = 0.75

then multiply: 0.75 x 60 = 45

3 0

3 years ago

Question regarding logarithms.

Eddi Din [679]

$5^{x-2}-7^{x-3}=7^{x-5}+11\cdot5^{x-4}\\\\5^{x-2}-7^{x-2-1}=7^{x-2-3}+11\cdot5^{x-2-2}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\5^{x-2}-\dfrac{7^{x-2}}{7^1}=\dfrac{7^{x-2}}{7^3}+11\cdot\dfrac{5^{x-2}}{5^2}\\\\5^{x-2}-\dfrac{1}{7}\cdot7^{x-2}=\dfrac{1}{343}\cdot7^{x-2}+\dfrac{11}{25}\cdot5^{x-2}\\\\-\dfrac{1}{7}\cdot7^{x-2}-\dfrac{1}{343}\cdot7^{x-2}=\dfrac{11}{25}\cdot5^{x-2}-5^{x-2}\\\\\left(-\dfrac{1}{7}-\dfrac{1}{343}\right)\cdot7^{x-2}=\left(\dfrac{11}{25}-1\right)\cdot5^{x-2}$

$\left(-\dfrac{49}{343}-\dfrac{1}{343}\right)\cdot7^{x-2}=-\dfrac{14}{25}\cdot5^{x-2}\\\\-\dfrac{50}{343}\cdot7^{x-2}=-\dfrac{14}{25}\cdot5^{x-2}\qquad\text{multiply both sides by}\ \left(-\dfrac{25}{14}\right)\\\\\dfrac{50\cdot25}{343\cdot14}\cdot7^{x-2}=5^{x-2}\qquad\text{divide both sides by}\ 7^{x-2}\\\\\dfrac{25\cdot25}{343\cdot7}=\dfrac{5^{x-2}}{7^{x-2}}\qquad\text{use}\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}$

$\dfrac{5^2\cdot5^2}{7^3\cdot7}=\left(\dfrac{5}{7}\right)^{x-2}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\\dfrac{5^4}{7^4}=\left(\dfrac{5}{7}\right)^{x-2}\\\\\left(\dfrac{5}{7}\right)^4=\left(\dfrac{5}{7}\right)^{x-2}\iff x-2=4\qquad\text{add 2 to both sides}\\\\\boxed{x=6}$

6 0

3 years ago

Read 2 more answers

Find the measure of angle x in the figure below.

baherus [9]

X = 180 - 58 - y
Y = 180- 126= 54
X= 180 - 58 - 54
X= 180- 112= 68 degrees

4 0

2 years ago