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3 years ago

A cube has a surface area of 3,750 Square feet how do I find the length of one side

Mathematics

2 answers:

bija089 [108]3 years ago

7 0

I believe the answer is 25.
25^6=3750

Dmitrij [34]3 years ago

6 0

What is the surface area of a cube? well the cube has 6 sides all squares (lenght+width)the volume of a cube is just the areas of a side the hieght (or lenght or width since they are equal) so given that the cubes surface area is 3750 sq ft you should be able to find the area of one side then take the square root to find the lenght of one lenght at one edge and use that to find he volume and the answer is 15625 cubic feet

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Help on #51 please !!

Aleks04 [339]

Answer:

53. ±6

51. 2

Step-by-step explanation:

According to the Order of Operations [GEMS\BOMDAS\PEMDAS etc.], in this case, evaluate everything in grouping symbols first, then evaluate the exponents to avoid confusion:

$\sqrt{(32 + {2}^{3} - 4)} = \sqrt{32 + 8 - 4} = \sqrt{36} = ±6 \\ \\ (17 - 11 + {4}^{2}) \div 11 = (17 - 11 + 16) \div 11 = \\ \\ 22 \div 11 = 2$

I am joyous to assist you anytime.

4 0

3 years ago

Given: Isosceles TriangleDEF. The measure of vertex Angle D is four times the measure of each base angle E and F.

777dan777 [17]

Answer:

D = 120° , E = 30° , F = 30°

Step-by-step explanation:

Let D = 4x

Let E&F = x

4x + x + × = 180°[angles in triangle is 180°]

6x = 180°

x = 180/6

x = 30°

E = 30°

F =30°

D =4(30°)

=120°

(Correct me if i am wrong)

4 0

3 years ago

What is 0.11 as a fraction in simplest form

bazaltina [42]

11 hundredths , or 11/100

3 0

3 years ago

the initial vertical velocity of a rocket shot straight up is 42 meters per second. How long does it take for the rocket to retu

Snowcat [4.5K]

It takes 4.3 seconds for the rocket to return to earth.

The equation is:
$0=-9.8t^2+v_0t+h_0$
where -9.8m/sec² is the acceleration due to gravity, v₀ is the initial velocity, and h₀ is the initial height. We will go from the assumption that the rocket is launched from the ground, so h₀=0, and we are told that the initial velocity, v₀, is 42. This gives us:

$0=-9.8t^2+42t$

We will use the quadratic formula to solve this. The quadratic formula is:
$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Plugging in our information we have:
$t=\frac{-42\pm \sqrt{42^2-4(-9.8)(0)}}{2(-9.8)}
\\
\\=\frac{-42\pm \sqrt{1764-0}}{-19.6}
\\
\\=\frac{-42\pm \sqrt{1764}}{-19.6}
\\
\\=\frac{-42\pm 42}{-19.6}=\frac{-42-42}{-19.6} \text{ or } \frac{-42+42}{-19.6}
\\
\\=\frac{-84}{-19.6}\text{ or }\frac{0}{-19.6}
\\
\\=4.3\text{ or }0$

x=0 is when the rocket is launched; x=4.3 is when the rocket lands.

8 0

3 years ago

Find x and y? <br>i dont want to cheat but can anyone tell me how to do it or how to start out

mash [69]

Answer:

x is 13

y is 39

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers