Answer:
D is the answer I think......
Let the required equation be y = mx + c; where y = 1, m = f'(0), x = 0
f(a) = sec(a)
f'(a) = sec(a)tan(a)
f'(0) = sec(0)tan(0) = 0
y = mx + c
1 = 0(0) + c
c = 1
Therefore, required equation is
y = 1.
Answer: 22.5 . The weight of the elephant is "22.5 times greater" than the weight of the lion.
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Explanation:
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(weight of lion) * (x) = (eight of the elephant) ; Solve for "x" .
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→ Divide each side of the equation by "(weight of lion)" ;
to isolate "x" on one side of the equation ; and to solve for "x" ;
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→ (weight of lion)*(x) / (weight of lion) = (weight of the elephant) /
(weight of lion) ;
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→ x = (weight of the elephant) / (weight of lion) ;
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→ Plug in our "given values" ; and solve for "x" ;
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→ x = (<span>9*10</span>³) / (4*10²) = (9*10⁽³⁻²⁾) / 4 = (9*10¹) / 4 ;
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→ x = 90 /4 = 25/2 = 22.5 ; which is our answer.
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No i dont think so but i could be wrong i will double check to be sure though