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VikaD [51]
2 years ago
5

Help please

Mathematics
1 answer:
Digiron [165]2 years ago
7 0

Answer:

Option C.

Step-by-step explanation:

Shortest way to solve this question is to find the factors of the given expression.

The given expression is (x² + 13).

Now we have to factorize it.

(x² + 13) = x² + (√13)²

            = x² + [-(i)²√(13)²]  [Since i = √(-1)]

            = x² - (i√13)²

            = (x - i√3)(x + i√3) [Since (a² - b²) = (a + b)(a - b)]

Option C will be the answer.

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PLEASE ANSWER ASASSP!!!!!!!!!!!!!!!!!!!!<br> Sovle the equation<br> 6 (y + 1.5) = -18<br> What is y?
Ede4ka [16]

Answer:

6(y+1.5)=-18

6y+9=-18 -9

6y=-27 ÷6

y=-4.5

Step-by-step explanation:

prove me wrong

7 0
3 years ago
Read 2 more answers
0.12x - 1.5= 0.24x - 0.06
Sophie [7]

To solve this equation, lets move all of the variables to one side of the equation and the constants to the other.

0.12x - 1.5 = 0.24x - 0.06

Subtract 0.12x from both sides of the equation

-1.5 = 0.12x - 0.06

Add 0.06 to both sides of the equation

-1.44 = 0.12x

Divide both sides by 0.12 to isolate x

x = -12

5 0
3 years ago
.,..................................
Masteriza [31]
What do you want us to answer??

7 0
3 years ago
I really need help finding the solution!!
Mrac [35]

Answer:

-0.5 is not a solution

2 is a solution

Step-by-step explanation:

To check if something is a solution of the equation, you need to substitute the value in place of the variable

15 + 2y = -12 - 4y

15 + 2(-0.5) = -12 - 4(-0.5)

15 - 1 = -12 + 2

14 ≠ -10 ∴ -0.5 is not a solution

5 - 2(3x + 5) = 3 - 10x

5 - 2[3(2) + 5] = 3 - 10(2)

5 - 2(6 + 5) = 3 - 10(2)

5 - 12 - 10 = 3 - 120

-17 = -17 ∴ 2 is a solution

3 0
2 years ago
A ____ of a triangle is the perpendicular segment from a vertex to the opposite side or to the line that contains the opposite s
blagie [28]

Answer:

Altitude

Step-by-step explanation:

An altitude of the triangle is the line segment from a vertex to the opposite side and perpendicular to the opposite side. The orthocenter will not always be inside the triangle. This is why the orthocenter is the point of concurrency of the lines containing the altitudes rather than just the altitudes.

8 0
2 years ago
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