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Finger [1]
3 years ago
9

Sam needs 7/8 cup mashed bananas and 5/6 cup mashed strawberries for a recipe. He wants to find whether he needs more bananas or

more strawberries. How can he write 7/8 and 5/6 as a pair of fractions with the smallest common denominator?
Mathematics
1 answer:
andrew11 [14]3 years ago
7 0

Answer:

I don't no the answer i hope you

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PLEASE HELP!! #8<br> k(x)=4x-2 on [3, 3+h]
zlopas [31]
X=h/4+5/4 is the correct answer
4 0
3 years ago
The air pressure inside Jason’s bike tires decreases by about 6% each week. The original pressure was 45 pounds per square inch
Brrunno [24]
Compound percentage reduction can be calculated by multiplying the initial number by (1-x)^t where x is the percentage reduction (/100, i.e. 1% reduction is 0.01), and t is the number of times it has reduced.

So:
a) p=45(1-0.06)^t=45*0.94^t
Where t is the number of weeks.

We can then just substitute in to work out the final pressure:
b) p = 45*0.94^6 = 31psi
5 0
3 years ago
Describe how you would estimate the first number of the quotion for the division497÷22
liraira [26]
I would round them so it would be 500 divided by 20
The answer should be close to 25
4 0
3 years ago
The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airp
motikmotik

Answer:

The 95% confidence interval for the population mean rating is (5.73, 6.95).

Step-by-step explanation:

We start by calculating the mean and standard deviation of the sample:

M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{50}(6+4+6+. . .+6)\\\\\\M=\dfrac{317}{50}\\\\\\M=6.34\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{49}((6-6.34)^2+(4-6.34)^2+(6-6.34)^2+. . . +(6-6.34)^2)}\\\\\\s=\sqrt{\dfrac{229.22}{49}}\\\\\\s=\sqrt{4.68}=2.16\\\\\\

We have to calculate a 95% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=6.34.

The sample size is N=50.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

s_M=\dfrac{s}{\sqrt{N}}=\dfrac{2.16}{\sqrt{50}}=\dfrac{2.16}{7.071}=0.305

The degrees of freedom for this sample size are:

df=n-1=50-1=49

The t-value for a 95% confidence interval and 49 degrees of freedom is t=2.01.

The margin of error (MOE) can be calculated as:

MOE=t\cdot s_M=2.01 \cdot 0.305=0.61

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 6.34-0.61=5.73\\\\UL=M+t \cdot s_M = 6.34+0.61=6.95

The 95% confidence interval for the mean is (5.73, 6.95).

4 0
3 years ago
Help!!!!PLEASE &amp; THANKS
kiruha [24]

x° = 25°

25° is the answer

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2 years ago
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