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2 years ago

20 points helpppppppppppppppppppppppppppppPLZZ anyone solve this ASAP

Mathematics

1 answer:

Sonja [21]2 years ago

4 0

Answer:

$cos^{-1}(cos\frac{ 7π}{6})=cos^{-1}(cos\frac{7*180}{6})$

$cos^{-1}(cos{210})$

$cos^{-}(cos(180+30))$

[since in third quadrant cos 30=- $\frac{\sqrt{3}}{2}]$

$cos^{-}(- \frac{\sqrt{3}}{2})$

:150°or $\frac{5π}{6}$

150°or  $\frac{5π}{6}$ is a required answer.

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This figure shows the procedure for constructing a

dangina [55]

Constructing What? you did not finish the question

8 0

2 years ago

Last Monday, two law students met up at café Literatura after school to read the pages they were assigned in the legal methods c

jonny [76]

Answer:

$N_{a} = T_{a}$

$N_{c} = 2 \times T_{c}$

Step-by-step explanation:

Alejandro has read 28 pages so far and he can read 1 page per minute.

Again, Carly has read 12 pages so far and he can read 2 pages per minute.

If the variable N represents the number of pages read by the readers and T in minutes represents the time spent by the reader to read this number of pages, then

For Alejandro: $N_{a} = 1 \times T_{a} = T_{a}$ ......... (1)

For Carly: $N_{c} = 2 \times T_{c}$ .......... (2)

So, the equations (1) and (2) gives the number of pages that Alejandro and Carly read. (Answer)

4 0

2 years ago

If (2i/2+i)-(3i/3+i)=a+bi, then a= A. 1/10 B. -10 C. 1/50 D. -1/10

Verizon [17]

Answer:

Option A is correct.

Step-by-step explanation:

We are given:

$\frac{2i}{2+i}-\frac{3i}{3+i} = a+bi$

We need to find the value of a.

The LCM of (2+i) and (3+i) is (2+i)(3+i)

$=\frac{2i(3+i)}{(2+i)(3+i)}-\frac{3i(2+i)}{(2+i)(3+i)}\\=\frac{6i+2i^2}{(2+i)(3+i)}-\frac{6i+3i^2}{(2+i)(3+i)}\\=\frac{6i+2i^2-(6i+3i^2)}{(2+i)(3+i)}\\=\frac{6i+2i^2-6i-3i^2)}{5+5i}\\=\frac{-i^2}{5+5i}\\i^2=-1\\=\frac{-(-1)}{5+5i}\\=\frac{1}{5+5i}$

Now rationalize the denominator by multiplying by 5-5i/5-5i

$=\frac{1}{5+5i}*\frac{5-5i}{5-5i} \\=\frac{5-5i}{(5+5i)(5-5i)}\\=\frac{5-5i}{(5+5i)(5-5i)}\\(a+b)(a-b)= a^2-b^2\\=\frac{5(1-i)}{(5)^2-(5i)^2}\\=\frac{5(1-i)}{25+25}\\=\frac{5(1-i)}{50}\\=\frac{1-i}{10}\\=\frac{1}{10}-\frac{i}{10}$

We are given

$\frac{2i}{2+i}-\frac{3i}{3+i} = a+bi$

Now after solving we have:

$\frac{1}{10}-\frac{i}{10}=a+bi$

So value of a = 1/10 and value of b = -1/10

So, Option A is correct.

8 0

3 years ago

-15+6p=5(2p+1) muti step

konstantin123 [22]

-15+6p= 10p+5
-15-5 = 10p-6p
-20 = 4p
P= -20/4
P= -5

7 0

2 years ago

Please answer correctly !!!!! Will mark Brianliest !!!!!!!!!!!!!!

Makovka662 [10]

The answer is 26.19. It’s 100% right.

4 0

2 years ago

20 points helpppppppppppppppppppppppppppppPLZZ anyone solve this ASAP​

20 points helpppppppppppppppppppppppppppppPLZZ anyone solve this ASAP