Answer: 2.17 g of bromide product would be formed
Explanation:
The reaction of calcium bromide with lithium oxide will be:
To calculate the moles :
As lithium oxide is in excess, calcium bromide is the limiting reagent.
According to stoichiometry :
1 mole of produce = 2 moles of
Thus 0.0125 moles of will require= of
Mass of
Thus 2.17 g of bromide product would be formed
Answer:
1.99V
Explanation:
Balanced redox reaction equation:
3CU2+(aq) + 2Al(s) ------> 3Cu(s) + 2Al3+(aq)
E°cell= E°cathode- E°anode
E°cell= 0.34-(-1.66)
E°cell= 2.0V
From Nernst equation:
E= E°cell - 0.0592/n logQ
E= 2.0 - 0.0592/6 log [3.43]/[1.63]
E= 2.0- 0.0032
E= 1.99V
<u>Answer:</u> The wavelength of light is
<u>Explanation:</u>
To calculate the wavelength of light, we use Rydberg's Equation:
Where,
= Wavelength of radiation
= Rydberg's Constant =
= Higher energy level = 7
= Lower energy level = 2
Putting the values in above equation, we get:
Converting this into nanometers, we use the conversion factor:
So,
Hence, the wavelength of light is
Answer:
c
Explanation:
it is c but im not exactly sure
you have a 25% chance tho
sorry