<span>D) Eectrons in covalent bonds are not always shared equally.</span>
Given:
7.20 g sample of Al2(SO4)3
Required:
Mass of oxygen
Solution:
Since you are not given a
chemical reaction, just base your solution to the chemical formula given.
Molar mass of Al2(SO4)3 = 342.15 g/mol
7.20 g Al2(SO4)3 (1 mol/342.15g)(3mol O/2 mol Al)(1 mol O2/1/2 mol
O2)(32g O2/1mol O2) = 4.04 g O2
Answer:
Basically, it is asking you to give an example of something that could replace nitrogen in the chemical, but would still produce the same result.
Answer: It is true about the type of reaction that it is a single replacement reaction, and the cations in the two ionic compounds are different.
Explanation:
When one element in a compound is replaced by another element in a chemical reaction then it is called a single replacement reaction.
For example,
Here, potassium metal is replacing the sodium metal in the sodium chloride compound.
As metals become cation by losing an electron in a chemical reaction.
Thus, we can conclude that it is true about the type of reaction that it is a single replacement reaction, and the cations in the two ionic compounds are different.
Answer:
113.4g of N2
Explanation:
Step 1:
The balanced equation for the reaction.
N2 + 3H2 —> 2NH3
Step 2:
Determination of the mass of N2 and H2 that reacted from the balanced equation. This is illustrated below:
Molar mass of N2 = 2x14 = 28g/mol
Mass of N2 from the balanced equation = 1 x 28 = 28g
Molar mass of H2 = 2x1 = 2g/mol
Mass of H2 from the balanced equation = 3 x 2 = 6g
From the balanced equation above, 28g of N2 reacted with 6g of H2.
Step 3:
Determination of the mass N2 required to react with 24.3g of H2.
The mass of N2 required to react with 24.3g of H2 can be obtained as follow:
From the balanced equation above, 28g of N2 reacted with 6g of H2.
Therefore, Xg of N2 will react 24.3g of H2 i.e
Xg of N2 = (28 x 24.3)/6
Xg of N2 = 113.4g
Therefore, 113.4g of N2 is required to react completely with 24.3g of H2.