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navik [9.2K]
3 years ago
15

4. A serving of cereal contains about of protein 9 mg 9 g 90 g 9 kg

Chemistry
1 answer:
aleksandrvk [35]3 years ago
7 0

Answer:

probably 90 g

Explanation:

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How many liters of C3H6O are present in a sample weighing 25.6 grams?
Romashka [77]

Answer:

V = 0.0327 L.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the liters of C3H6O by the definition of density. We can tell the density of this substance as that of acetone (0.784 g/mL) and therefore calculate the liters as shown below:

V=25.6g*\frac{1mL}{0.784g}*\frac{1L}{1000mL}\\\\V=0.0327L

Regards!

7 0
3 years ago
What is the chemical formula for iodine gas?​
DanielleElmas [232]

Answer:

I2

hope this helps

3 0
3 years ago
Read 2 more answers
If 7.35 L of gas at 17°C and 3.55 atm is compressed at a pressure of 123 atm and 34°C, calculate the
MaRussiya [10]

Answer: V2= 0.224L

Explanation:

P1=3.55atm, V2= 7.35L, T1= 290, P2= 123atm, V2=?, T2= 307K

Applying general gas equation

P1V1/T1= P2V2/T2

Substitute and Simplify

3.55×7.35/290 = 123×V2/307

V2= 0.224L

6 0
3 years ago
What is the name of the ionic compound cao
frosja888 [35]

The name of this Ionic Compound is Calcium oxide.

7 0
3 years ago
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When 100.0 g block of a metal at 600 oC is plunged into 100.0 g of water (specific heat capacity 4.2 J/g.oC) at 30 oC, the final
kozerog [31]

Answer:  0.40J/g^0C

Explanation:

heat_{released}=heat_{absorbed}

As we know that,  

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

-[m_1\times c_1\times (T_{final}-T_1)]=[m_2\times c_2\times (T_{final}-T_2)]         .................(1)

where,

q = heat absorbed or released

m_1 = mass of metal = 100.0 g

m_2 = mass of water = 100.0 g

T_{final} = final temperature = 80^0C

T_1 = temperature of metal = 600^oC

T_2 = temperature of water = 30^oC

c_1 = specific heat of metal = ?

c_2 = specific heat of water= 4.2J/g^0C

Now put all the given values in equation (1), we get

-[100.0\times c_1\times (80-600)]=[100.0\times 4.2\times (80-30)]

c_1=0.404J/g^0C

Therefore, the specific heat capacity of metal is c_1=0.40J/g^0C

4 0
3 years ago
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