Ask question

Ask question

All categories

3 years ago

14

Consider the function f(x)=a sin(bc+c). which of the following combinations of parameter values will result in a graph of f(x) i

dentical to that of the parent function, sin x?
a=-1; b=1; c=pi/2
a=1/2; b=2; c=0
a=1; b=-1; c=pi/2
a=1; b=-1; c=pi

1 answer:

7nadin3 [17]3 years ago

5 0

Answer:

D. a=1; b=-1; c=pi

You might be interested in

Which sequence or sequences are correct and why?

inessss [21]

Answer:

didn't get the question did u forget to put the sequence ???????

pls write the question fully so that I can help you

4 0

3 years ago

You ask a neighbor to water a sickly plant while you are on vacation. Without water the plant will die with probability 0.7. Wit

Lina20 [59]

Answer:

0.2416

Step-by-step explanation:

P(forgot to water | dead) = P(forgot and dead) / P(dead)

->With water it will die with probability 0.45

P(watered and dead) =0.83 x 0.45 = 0.3735

->Without water the plant will die with probability 0.7

P(forgot and dead) = (1-0.83) x 0.7 => 0.17 x 0.7 =>0.119

P(dead) = P(watered and dead) +P(forgot and dead)

P(dead) = 0.3735 + 0.119= 0.4925

P(forgot to water | dead) =0.119 / 0.4925= 0.2416

Therefore, the probability the neighbor forgot to water the plant is 0.2416

8 0

3 years ago

Which ordered pair is the solution to the system of linear equations y= -7x+2 and. y=9x - 14

12345 [234]

The answer is (1,-5), If you put those two on a graph, that point is where they collide.

6 0

3 years ago

Lin and Tyler are drawing circles. Tyler’s circle has twice the diameter of lins circle. Tyler thinks that his circle will have

Allushta [10]

Answer:

No

Step-by-step explanation:

Ratio of areas = (Ratio of diameters)²

Ratio of areas = 2² = 4

7 0

3 years ago

Read 2 more answers

Use Newton’s Method to find the solution to x^3+1=2x+3 use x_1=2 and find x_4 accurate to six decimal places. Hint use x^3-2x-2=

luda_lava [24]

Let $f(x) = x^3 - 2x - 2$ . Then differentiating, we get

$f'(x) = 3x^2 - 2$

We approximate $f(x)$ at $x_1=2$ with the tangent line,

$f(x) \approx f(x_1) + f'(x_1) (x - x_1) = 10x - 18$

The $x$ -intercept for this approximation will be our next approximation for the root,

$10x - 18 = 0 \implies x_2 = \dfrac95$

Repeat this process. Approximate $f(x)$ at $x_2 = \frac95$ .

$f(x) \approx f(x_2) + f'(x_2) (x-x_2) = \dfrac{193}{25}x - \dfrac{1708}{125}$

Then

$\dfrac{193}{25}x - \dfrac{1708}{125} = 0 \implies x_3 = \dfrac{1708}{965}$

Once more. Approximate $f(x)$ at $x_3$ .

$f(x) \approx f(x_3) + f'(x_3) (x - x_3) = \dfrac{6,889,342}{931,225}x - \dfrac{11,762,638,074}{898,632,125}$

Then

$\dfrac{6,889,342}{931,225}x - \dfrac{11,762,638,074}{898,632,125} = 0 \\\\ \implies x_4 = \dfrac{5,881,319,037}{3,324,107,515} \approx 1.769292663 \approx \boxed{1.769293}$

Compare this to the actual root of $f(x)$ , which is approximately <u>1.76929</u>2354, matching up to the first 5 digits after the decimal place.

4 0

2 years ago