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nata0808 [166]
3 years ago
8

Use the function below to find f(2). f(x)=1/3•4^x

Mathematics
2 answers:
xenn [34]3 years ago
6 0
To find f(2), you just need to replace x for 2.
1/3•4^(2)
The answer is 16/3 or 5.3333...
scZoUnD [109]3 years ago
4 0

Answer: 16/3

Hope this helps !!!

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Factor the trinomial x^2 - 2x - 8
ValentinkaMS [17]
Well what two numbers multiply to get -8 and add to get -2?
Well, to get -8, we either have (-1,8),(-2,4),(-4,2),(-8,1)
8-1=7
-2+4=2
2-4=-2
1-8=-7
Thus it should be (-4,2),
This means we should get (X-4)(X+2)
7 0
3 years ago
PLEASE HELPPP!!!!!! Write an equation of the line passing through point P that is perpendicular to the given line.
ArbitrLikvidat [17]

Answer:(d): y=ax+b (a≠0); (d1)y=-4x+13

because of (d)⊥(d1) --> a.(-4)=-1 --> a=\frac{1}{4}

(d): y=\frac{1}{4}x+b. (d) pass through  P(-1;-2) so we have

-2=(1/4).(-1)+b ---> b=\frac{-7}{4}

(d) y= \frac{1}{4}x+ \frac{-7}{4}

4 0
3 years ago
Ethan ill do 3 questions at a time :)
pashok25 [27]
1.) Number of Total Shirts = 220

In Figure 1, Red boxes represent "<span>short sleeve shirts" which is 7 in number whereas Blue boxes represent "long sleeve shirts".

1 box contains = 220/10 = 22 shirts 

Number of short sleeves = 22 * 7 = 154

<span>In short, Your Final Answer would be: 154 

</span></span>2.) Number of Total Subscribers = 260

In Figure 1, Red boxes represent "<span>regular subscribers" which is 10 in number whereas Blue boxes represent "premium subscribers".

1 box contains = 260/13 = 20 subscribers. 

Regular subscribers = 20 * 10 = 200 

<span>In short, Your Final Answer would be: 200
</span></span>
3.) Number of Total People = 360

In Figure 1, Red boxes represent "<span>Males" which is 3 in number whereas Blue boxes represent "females".

1 box contains = 360/12 = 30 people

Number of males: = 30 * 3 = 90

<span>In short, Your Final Answer would be: 90

Hope this helps!
</span></span>

7 0
3 years ago
Read 2 more answers
Explain how to multiply the following whole numbers 21 x 14
Lesechka [4]

Answer:

\begin{matrix}\space\space&\textbf{2}&\textbf{1}\\ \times \:&1&\textbf{4}\end{matrix}

________

\frac{\begin{matrix}\space\space&\textbf{0}&8&4\\ +&\textbf{2}&1&0\end{matrix}}{\begin{matrix}\space\space&\textbf{2}&9&4\end{matrix}}

Step-by-step explanation:

Given

21\:\times \:14

Line up the numbers

\begin{matrix}\space\space&2&1\\ \times \:&1&4\end{matrix}

Multiply the top number by the bottom number one digit at a time starting with the ones digit left(from right to left right)

Multiply the top number by the bolded digit of the bottom number

\begin{matrix}\space\space&\textbf{2}&\textbf{1}\\ \times \:&1&\textbf{4}\end{matrix}

Multiply the bold numbers:    1×4=4

\frac{\begin{matrix}\space\space&2&\textbf{1}\\ \times \:&1&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&\space\space&4\end{matrix}}

Multiply the bold numbers:    2×4=8

\frac{\begin{matrix}\space\space&\textbf{2}&1\\ \times \:&1&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&8&4\end{matrix}}

Multiply the top number by the bolded digit of the bottom number

\frac{\begin{matrix}\space\space&\textbf{2}&\textbf{1}\\ \times \:&\textbf{1}&4\end{matrix}}{\begin{matrix}\space\space&8&4\end{matrix}}

Multiply the bold numbers:    1×1=1

\frac{\begin{matrix}\space\space&\space\space&2&\textbf{1}\\ \space\space&\times \:&\textbf{1}&4\end{matrix}}{\begin{matrix}\space\space&\space\space&8&4\\ \space\space&\space\space&1&\space\space\end{matrix}}

Multiply the bold numbers:    2×1=2

\frac{\begin{matrix}\space\space&\space\space&\textbf{2}&1\\ \space\space&\times \:&\textbf{1}&4\end{matrix}}{\begin{matrix}\space\space&\space\space&8&4\\ \space\space&2&1&\space\space\end{matrix}}

Add the rows to get the answer. For simplicity, fill in trailing zeros.

\frac{\begin{matrix}\space\space&\space\space&2&1\\ \space\space&\times \:&1&4\end{matrix}}{\begin{matrix}\space\space&0&8&4\\ \space\space&2&1&0\end{matrix}}

adding portion

\begin{matrix}\space\space&0&8&4\\ +&2&1&0\end{matrix}

Add the digits of the right-most column: 4+0=4

\frac{\begin{matrix}\space\space&0&8&\textbf{4}\\ +&2&1&\textbf{0}\end{matrix}}{\begin{matrix}\space\space&\space\space&\space\space&\textbf{4}\end{matrix}}

Add the digits of the right-most column: 8+1=9

\frac{\begin{matrix}\space\space&0&\textbf{8}&4\\ +&2&\textbf{1}&0\end{matrix}}{\begin{matrix}\space\space&\space\space&\textbf{9}&4\end{matrix}}

Add the digits of the right-most column: 0+2=2

\frac{\begin{matrix}\space\space&\textbf{0}&8&4\\ +&\textbf{2}&1&0\end{matrix}}{\begin{matrix}\space\space&\textbf{2}&9&4\end{matrix}}

Therefore,

\begin{matrix}\space\space&\textbf{2}&\textbf{1}\\ \times \:&1&\textbf{4}\end{matrix}

________

\frac{\begin{matrix}\space\space&\textbf{0}&8&4\\ +&\textbf{2}&1&0\end{matrix}}{\begin{matrix}\space\space&\textbf{2}&9&4\end{matrix}}

6 0
3 years ago
Please help me someone ASAP
Artyom0805 [142]
The Answer is b. Hope that helps
5 0
3 years ago
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