All categories

3 years ago

Use the function below to find f(2). f(x)=1/3•4^x

Mathematics

2 answers:

xenn [34]3 years ago

6 0

To find f(2), you just need to replace x for 2.
1/3•4^(2)
The answer is 16/3 or 5.3333...

scZoUnD [109]3 years ago

4 0

Answer: 16/3

Hope this helps !!!

You might be interested in

Factor the trinomial x^2 - 2x - 8

ValentinkaMS [17]

Well what two numbers multiply to get -8 and add to get -2?
Well, to get -8, we either have (-1,8),(-2,4),(-4,2),(-8,1)
8-1=7
-2+4=2
2-4=-2
1-8=-7
Thus it should be (-4,2),
This means we should get (X-4)(X+2)

7 0

3 years ago

PLEASE HELPPP!!!!!! Write an equation of the line passing through point P that is perpendicular to the given line.

ArbitrLikvidat [17]

Answer:(d): y=ax+b (a≠0); (d1)y=-4x+13

because of (d)⊥(d1) --> a.(-4)=-1 --> a= $\frac{1}{4}$

(d): y= $\frac{1}{4}x$ +b. (d) pass through P(-1;-2) so we have

-2=(1/4).(-1)+b ---> b= $\frac{-7}{4}$

(d) y= $\frac{1}{4}x+ \frac{-7}{4}$

4 0

3 years ago

Ethan ill do 3 questions at a time :)

pashok25 [27]

1.) Number of Total Shirts = 220

In Figure 1, Red boxes represent "short sleeve shirts" which is 7 in number whereas Blue boxes represent "long sleeve shirts".

1 box contains = 220/10 = 22 shirts

Number of short sleeves = 22 * 7 = 154

In short, Your Final Answer would be: 154

2.) Number of Total Subscribers = 260

In Figure 1, Red boxes represent "regular subscribers" which is 10 in number whereas Blue boxes represent "premium subscribers".

1 box contains = 260/13 = 20 subscribers.

Regular subscribers = 20 * 10 = 200

In short, Your Final Answer would be: 200

3.) Number of Total People = 360

In Figure 1, Red boxes represent "Males" which is 3 in number whereas Blue boxes represent "females".

1 box contains = 360/12 = 30 people

Number of males: = 30 * 3 = 90

In short, Your Final Answer would be: 90

Hope this helps!

7 0

3 years ago

Read 2 more answers

Explain how to multiply the following whole numbers 21 x 14

Lesechka [4]

Answer:

$\begin{matrix}\space\space&\textbf{2}&\textbf{1}\\ \times \:&1&\textbf{4}\end{matrix}$

________

$\frac{\begin{matrix}\space\space&\textbf{0}&8&4\\ +&\textbf{2}&1&0\end{matrix}}{\begin{matrix}\space\space&\textbf{2}&9&4\end{matrix}}$

Step-by-step explanation:

Given

$21\:\times \:14$

Line up the numbers

$\begin{matrix}\space\space&2&1\\ \times \:&1&4\end{matrix}$

Multiply the top number by the bottom number one digit at a time starting with the ones digit left(from right to left right)

Multiply the top number by the bolded digit of the bottom number

$\begin{matrix}\space\space&\textbf{2}&\textbf{1}\\ \times \:&1&\textbf{4}\end{matrix}$

Multiply the bold numbers: 1×4=4

$\frac{\begin{matrix}\space\space&2&\textbf{1}\\ \times \:&1&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&\space\space&4\end{matrix}}$

Multiply the bold numbers: 2×4=8

$\frac{\begin{matrix}\space\space&\textbf{2}&1\\ \times \:&1&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&8&4\end{matrix}}$

Multiply the top number by the bolded digit of the bottom number

$\frac{\begin{matrix}\space\space&\textbf{2}&\textbf{1}\\ \times \:&\textbf{1}&4\end{matrix}}{\begin{matrix}\space\space&8&4\end{matrix}}$

Multiply the bold numbers: 1×1=1

$\frac{\begin{matrix}\space\space&\space\space&2&\textbf{1}\\ \space\space&\times \:&\textbf{1}&4\end{matrix}}{\begin{matrix}\space\space&\space\space&8&4\\ \space\space&\space\space&1&\space\space\end{matrix}}$

Multiply the bold numbers: 2×1=2

$\frac{\begin{matrix}\space\space&\space\space&\textbf{2}&1\\ \space\space&\times \:&\textbf{1}&4\end{matrix}}{\begin{matrix}\space\space&\space\space&8&4\\ \space\space&2&1&\space\space\end{matrix}}$

Add the rows to get the answer. For simplicity, fill in trailing zeros.

$\frac{\begin{matrix}\space\space&\space\space&2&1\\ \space\space&\times \:&1&4\end{matrix}}{\begin{matrix}\space\space&0&8&4\\ \space\space&2&1&0\end{matrix}}$

adding portion

$\begin{matrix}\space\space&0&8&4\\ +&2&1&0\end{matrix}$

Add the digits of the right-most column: 4+0=4

$\frac{\begin{matrix}\space\space&0&8&\textbf{4}\\ +&2&1&\textbf{0}\end{matrix}}{\begin{matrix}\space\space&\space\space&\space\space&\textbf{4}\end{matrix}}$

Add the digits of the right-most column: 8+1=9

$\frac{\begin{matrix}\space\space&0&\textbf{8}&4\\ +&2&\textbf{1}&0\end{matrix}}{\begin{matrix}\space\space&\space\space&\textbf{9}&4\end{matrix}}$

Add the digits of the right-most column: 0+2=2

$\frac{\begin{matrix}\space\space&\textbf{0}&8&4\\ +&\textbf{2}&1&0\end{matrix}}{\begin{matrix}\space\space&\textbf{2}&9&4\end{matrix}}$

Therefore,

$\begin{matrix}\space\space&\textbf{2}&\textbf{1}\\ \times \:&1&\textbf{4}\end{matrix}$

________

$\frac{\begin{matrix}\space\space&\textbf{0}&8&4\\ +&\textbf{2}&1&0\end{matrix}}{\begin{matrix}\space\space&\textbf{2}&9&4\end{matrix}}$

6 0

3 years ago

Please help me someone ASAP

Artyom0805 [142]

The Answer is b. Hope that helps

5 0

3 years ago