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3 years ago

Please help fast. It’s a test

Mathematics

2 answers:

Reil [10]3 years ago

6 0

Were is the question?

Setler [38]3 years ago

4 0

Answer:

what do you need help with

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The latest mystery novel cost $24 the table shows the sales of that this novel by a bookstore what was the dollar amount of the

Ket [755]

Answer:

$3768

Step-by-step explanation:

The amount of sales will be the product of the selling price of each book and the number of books sold.

sales = book price × number of books

sales = $24 × 157 . . . . . . . . books sold on Saturday

sales = $3768 . . . . . . . . . . . sales on Saturday

4 0

3 years ago

Ebony earns $2,000 per month. If she spends $450 on rent each month, what percent of her income does she spend on rent?

Arte-miy333 [17]

22.5 so the answer is A

4 0

3 years ago

Read 2 more answers

You have recorded your car mileage and gasoline use for 5 weeks. Estimate the number of miles you can drive on a full 15-gallon

I am Lyosha [343]

Answer:

325 miles to the nearest mile.

Step-by-step explanation:

Average gasoline consumption over the 5 weeks

= miles travelled / gasoline used

= (198 + 115 + 154 + 160 + 132) / (9 + 5 + 7 + 8 + 6)

= 21.69 miles per gallon.

Estimate of number of miles you can drive on 15 gallons

= 15 * 21.69

= 325 miles.

4 0

4 years ago

ELE HOME 19. Which expression is equivalent to (7 x m) + 5? O A7(m + 5) O B7 + 5m O C 5+ (m x 7) O D 5- (7 x m)

SVETLANKA909090 [29]

Answer:

Step-by-step explanation:

4 0

3 years ago

PLS HELP ME!!!!!!!! 99 POINTS

Amiraneli [1.4K]

Answer:

$\angle LKN=\arctan1.8\sqrt{97}\approx 86.77^{\circ}$

Step-by-step explanation:

Draw the second altitude MB (see attached diagram).

Quadrilateral HLMB is a rectangle, then LM = HB = 3 units.

Trapezoid KLMN is isosceles trapezoid (because KL=MN), thus

$KH = BN = \dfrac{KN-HB}{2}=\dfrac{13-3}{2}=5\ units\\ \\HN=HB+BN=3+5=8\ units$

Triangle LHN is right triangle, then by Pythagorean theorem,

$LN^2=LH^2+HN^2\\ \\89^2=LH^2+8^2\\ \\LH^2=89^2-8^2\\ \\LH^2=(89-8)(89+8)\\ \\LH^2=81\cdot 97\\ \\LH=9\sqrt{97}\ units$

Consider right triangle KLH. In this triangle,

$\tan\angle LKH=\{\tan\angle LKH\}=\dfrac{\text{opposite leg}}{\text{adjacent leg}}=\dfrac{LH}{KH}=\dfrac{9\sqrt{97}}{5}=1.8\sqrt{97}\ units$

So,

$\angle LKN=\arctan1.8\sqrt{97}\approx 86.77^{\circ}$

5 0

3 years ago