X=45, X=62
X=73 thank me i am your savior I gave you the answer say thank you now you know
Answer:
(a) There are outliers
(b) 
and 
Step-by-step explanation:
Given
Solving (a): Check for outliers
This is calculated using:
--- lower bound of outlier
--- upper bound of outlier
Where
So, we have:
The lower bound of outlier becomes
The upper bound of outlier becomes
So, we have:
--- the range without outlier
Given that:
--- This represents the lowest data
--- This represents the highest data
-24 and 64 are out of range of .
Hence, there are outliers
Solving (b): The outliers
The outliers are data less than the lower bound (i.e. less than -14) or greater than the upper bound (i.e. 62)
So, the outliers are:
and
Answer:
<h3>The answer is option C</h3>
Step-by-step explanation:
6x³ - 4x² - 16x
To factorize the expression first factor out the GCF out
The GCF in the expression is 2x
That's
2x( 3x² - 2x - 8)
Next Factorize the terms in the bracket
To factorize write - 2x as a difference
that's
2x( 3x² + 4x - 6x - 8)
<u>Factor out x from the expression</u>
2x [ x( 3x + 4) - 6x - 8 ]
<u>Next factor out - 2 from the expression</u>
2x [ x ( 3x + 4) - 2( 3x + 4) ]
<u>Factor out 3x + 4 from the expression</u>
We have the final answer as
<h3>2x( 3x + 4)( x - 2)</h3>
Hope this helps you
Answer:
a = length of the base = 2.172 m
b = width of the base = 1.357 m
c = height = 4.072 m
Step-by-step explanation:
Suppose we want to build a rectangular storage container with open top whose volume is 12 cubic meters. Assume that the cost of materials for the base is 12 dollars per square meter, and the cost of materials for the sides is 8 dollars per square meter. The height of the box is three times the width of the base. What’s the least amount of money we can spend to build such a container?
lets call a = length of the base
b = width of the base
c = height
V = a.b.c = 12
Area without the top:
Area = ab + 2bc + 2ac
Cost = 12ab + 8.2bc + 8.2ac
Cost = 12ab + 16bc + 16ac
height = 3.width
c = 3b
Cost = 12ab + 16b.3b + 16a.3b = 12ab + 48b² + 48ab = 48b² + 60ab
abc = 12 → ab.3b = 12 → 3ab² = 12 → ab² = 4 → a = 4/b²
Cost = 48b² + 60ab = 48b² + 60b.4/b² = 48b² + 240/b
C(b) = 48b² + 240/b
C'(b) = 96b - 240/b²
Minimum cost: C'(b) = 0
96b - 240/b² = 0
(96b³ - 240)/b² = 0
96b³ - 240 = 0
96b³ = 240
b³ = 240/96
b³ = 2.5
b = 1.357m
c = 3b = 3*1.357 = 4.072m
a = 4/b² = 2.172m
Answer:
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