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STatiana [176]
2 years ago
8

Math Test Helpppppp!!!!!!!!

Mathematics
1 answer:
soldier1979 [14.2K]2 years ago
3 0
Simple problem:

When simplifying 3(x-6) they subtracted 3 instead of multiplied by 3.
3(x-6) should be 3x-18.
Now when you simplify:
3x-18+4x+12-6x
Which is x -6 =0
Or x =6
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A rope of length 18 feet is arranged in the shape of a sector of a circle with central angle O radians, as shown in the
creativ13 [48]

Answer:

A(\theta)=\frac{162 \theta}{(\theta+2)^2}

Step-by-step explanation:

The picture of the question in the attached figure

step 1

Let

r ---> the radius of the sector

s ---> the arc length of sector

Find the radius r

we know that

2r+s=18

s=r \theta

2r+r \theta=18

solve for r

r=\frac{18}{2+\theta}

step 2

Find the value of s

s=r \theta

substitute the value of r

s=\frac{18}{2+\theta}\theta

step 3

we know that

The area of complete circle is equal to

A=\pi r^{2}

The complete circle subtends a central angle of 2π radians

so

using proportion find the area of the sector by a central angle of angle theta

Let

A ---> the area of sector with central angle theta

\frac{\pi r^{2} }{2\pi}=\frac{A}{\theta} \\\\A=\frac{r^2\theta}{2}

substitute the value of r

A=\frac{(\frac{18}{2+\theta})^2\theta}{2}

A=\frac{162 \theta}{(\theta+2)^2}

Convert to function notation

A(\theta)=\frac{162 \theta}{(\theta+2)^2}

6 0
3 years ago
Justine answered 68 questions correctly on and 80 question test. Express this amount as a fraction percent and decimal
kupik [55]

Answer: 0.85 or %85

Fraction = 68 over 80 divide by two twice 17 over

                                                           20

Percent = 68/80 = 0.85 x 100 = 85%

Decimal =  0.85

3 0
2 years ago
Read 2 more answers
What is the length of AD? <br><br>A) 17<br>B) 15<br>C) 7<br>D) 1
kirill [66]

7+8= 15 so the second answer


5 0
3 years ago
Read 2 more answers
What is the missing exponent in the equation 2? = 16?
IRISSAK [1]

Answer:

4

Step-by-step explanation:

2x2x2x2 = 16

5 0
3 years ago
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Write an expression that has four terms. Your expression should have three different variables and a constant
raketka [301]
4m+5a+x-6 this is just one example you could switch it around it even use different numbers but that expression does have 4 terms, three different variables, and one constant, hope this helps:)
8 0
2 years ago
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