Let x represent the number of students in Janelle’s group.
If Janelle brings 3 markers for each person in her group, then she brings 3x markers for x students. You also know that she brings <span>5 extra markers for everyone to share. Thus, the total amount of markers she brings is 3x+5.
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If Janelle brings in 23 markers in all, then the equation <span><span>3x+5=23 </span> represaents the mathematical model. </span>
3x=23-5,3x=18,x=6
Answer: there are 6 students in Janelle's group.
Technically this is not necessarily true for all. A function has each input mapped to one output, therefore there can be two inputs that have the same output. However, when inverted, the input will have two outputs, which is not a function. For example with (1,3) (2,3) (3,4) (4,5) this is a function but switched (3,1) (3,2) ! Two inputs have the same output, which is not a function!
Answer:
prett sure it's b
Step-by-step explanation:
Given that the scale readings of the laboratory scale is normally distributed with an unknown mean and a standard deviation of 0.0002 grams.
Part A:
If the weight is weighted 5 times and the mean weight is 10.0023 grams, the 98% confidence interval for μ, the true mean of the scale readings is given by:
Thus, we are 98% confidence that the true mean of the scale readings is between 10.0021 and 10.0025.
Part B:
To get a margin of error of +/- 0.0001 with a 98% confidence, then
Therefore, the number of <span>measurements that must be averaged to get a margin of error of ±0.0001 with 98% confidence is 22.</span>
Answer:
The probability that a randomly chosen person has measles antibodies in his/her blood if the new test is positive = 0.9796
Step-by-step explanation:
The event that someone tests positive = P(T)
The event that someone has antibodies = P(A)
The event that someone does not have antibodies = P(A')
The new test was positive when administered to 96% of those who have the antibodies.
This probability = P(T n A) = 0.96
The new test gave positive results in 2% of those who do not have them.
This probability = P(T n A') = 0.02
The probability that a randomly chosen person has measles antibodies in his/her blood if the new test is positive = P(A|T)
This conditional probability is given as
P(A|T) = P(T n A) ÷ P(T)
P(T) is given as
P(T) = P(T n A) + P(T n A') = 0.96 + 0.02 = 0.98
P(A|T) = P(T n A) ÷ P(T) = 0.96 ÷ 0.98 = 0.9796
Hope this Helps!!!