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erik [133]
3 years ago
6

Solve five and three sixths minus two and one third.

Mathematics
2 answers:
KonstantinChe [14]3 years ago
6 0

Answer:

3and3/18

Step-by-step explanation:

4vir4ik [10]3 years ago
4 0

Answer:

Option 4: 3\frac{3}{18} is the correct answer.

Step-by-step explanation:

The given fractions are mixed fractions. the mixed fractions have to be converted into proper fractions before performing any operation like addition, subtraction etc.

Given fractions are:

5\frac{3}{6}-2\frac{1}{3}

Converting into proper fractions

=\frac{33}{6} - \frac{7}{3}

Making the denominator same

We have to multiply first fraction by 3 and second by 6

=\frac{33*3}{6*3} - \frac{7*6}{3*6}\\=\frac{99}{18}-\frac{42}{18}\\=\frac{99-42}{18}\\= \frac{57}{18}

Converting into mixed fraction: =3\frac{3}{18}

Hence,

Option 4: 3\frac{3}{18} is the correct answer.

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Write the absolute value inequality for the following: Do not solve.
Naddik [55]

Answer:

  |s -55| ≤ 3

Step-by-step explanation:

"Within 3 mph of 55 mph" means the magnitude of the difference between s and 55 is at most 3. In symbols, this is ...

  |s -55| ≤ 3

7 0
3 years ago
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Assume the readings on thermometers are normally distributed with a mean of 0degreesC and a standard deviation of 1.00degreesC.
Nat2105 [25]

Answer:

P(-2.05

And we can find this probability with this difference

P(-2.05

And we can see the figure in the plot attached.

Step-by-step explanation:

Let X the random variable that represent the redings on thermometers of a population, and for this case we know the distribution for X is given by:

X \sim N(0,1)  

Where \mu=0 and \sigma=1

We are interested on this probability

P(-2.05

We can use the z score formula given by:

z=\frac{x-\mu}{\sigma}

Using this formula we got:

P(-2.05

And we can find this probability with this difference

P(-2.05

And we can see the figure in the plot attached.

5 0
4 years ago
Here is my question: -7 times x = 189
RSB [31]
Hey buddy
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3 years ago
What is the surface area of this design
Alja [10]
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3 years ago
For what values (cases) of the variables the expression does not exist: b/a+b
Dmitry [639]

Answer:

The expression b/(a +b) does not exist when a = -b or b = -a

Step-by-step explanation:

The expression b/(a + b) does not exist if the denominator a + b = 0.

So, a = - b or b = -a.

So, the expression b/(a + b) does not exist when a = -b or b = -a.

When a = -b values, the denominator a + b = -b + b = 0. This will make the expression b/(a + b) = b/0 = ∞ which undefined or does not exist.

When b = -a values, the denominator a + b = a + (-a) = a - a = 0. This will make the expression b/(a + b) = -a/0 = -∞ which undefined or does not exist.

So the expression b/(a +b) does not exist when a = -b or b = -a

6 0
3 years ago
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