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Tju [1.3M]
3 years ago
10

Debra is buying prizes for a game at her school's fundraiser. The game has three levels of prizes, and she has already bought th

e second and third prizes. She wants the first prize to be nice enough to attract people to the game. The game's manufacturer has supplied her with the probabilities of winning first, second, and third prizes. Tickets cost $3 each, and she wants the school to profit an average of $1 per ticket. How much should she spend on each first prize
Mathematics
1 answer:
Yanka [14]3 years ago
4 0

Answer:

$9.19

Step-by-step explanation:

We are given that

Cost of each ticket=$3

Average profit per ticket=$1

Expect gain for ticket purchaser must be -$1

Let x be the cost of first prize

Probability of first prize=0.15

Probability of second prize=0.30

Probability of third prize=0.45

Cost of second prize=$1.15

Cost of third prize=$0.74

Total probability=0.15+0.30+0.45=0.9

Probability of winning =0.9

Probability of losing=1-0.9=0.1

According to question

x(0.15)+0.30(1.15)+0.74(0.45)-3(0.1)=-1

0.15x+0.378=-1

0.15x=-1-0.378

0.15x=-1.378

x=-\frac{1.378}{0.15}=-9.19

Hence, she spend money on each first prize=$9.19

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Drag steps of the solution into order to solve for x in the equation 6(x–5)=54.
Zanzabum
Alright first things first you need to distrubute 6(x-5) so that will be 6x-30=54
In order for you to get x by itself you need to add -30 on both sides so  that'll be your second step is to add -30 on both sides: -30+-30  54+-30. Cancel out -30 and add the 54 and -30 together and you'll get 24.
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So your answer will be x=4.

Hope this helped :)
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Answer:

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