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boyakko [2]
3 years ago
11

There are 12 boys and 12 girls in Trevor's math class. His teacher will randomly select one student to present a homework proble

m to the class. Describe two different ways that rolling a six-sided die could be used to simulate the probability that Trevor's teacher will select a boy or girl.
Mathematics
1 answer:
quester [9]3 years ago
5 0

Answer:

1/24

Step-by-step explanation:

1/24 bc there is 24 students in the class and the teachercould only choose 1 student

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Stella [2.4K]

Hello from MrBillDoesMath!

Answer:

81 ft^2

Discussion:

The area of a square is (length of a side)^2.  In this case,

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Read 2 more answers
Help me to answer this pls​
nlexa [21]

Problem 1

x = measure of angle N

2x = measure of angle M, twice as large as N

3(2x) = 6x = measure of angle O, three times as large as M

The three angles add to 180 which is true of any triangle.

M+N+O = 180

x+2x+6x = 180

9x = 180

x = 180/9

x = 20 is the measure of angle N

Use this x value to find that 2x = 2*20 = 40 and 6x = 6*20 = 120 to represent the measures of angles M and O in that order.

<h3>Answers:</h3>
  • Angle M = 40 degrees
  • Angle N = 20 degrees
  • Angle O =  120 degrees

====================================================

Problem 2

n = number of sides

S = sum of the interior angles of a polygon with n sides

S = 180(n-2)

2700 = 180(n-2)

n-2 = 2700/180

n-2 = 15

n = 15+2

n = 17

<h3>Answer: 17 sides</h3>

====================================================

Problem 3

x = smaller acute angle

3x = larger acute angle, three times as large

For any right triangle, the two acute angles always add to 90.

x+3x = 90

4x = 90

x = 90/4

x = 22.5

This leads to 3x = 3*22.5 = 67.5

<h3>Answers:</h3>
  • Smaller acute angle = 22.5 degrees
  • Larger acute angle = 67.5 degrees
4 0
1 year ago
Grace wants to find the probability of a family of 3 children having 2 boys and 1 girl. Use a tree diagram to list the possibili
pychu [463]

Answer:

Step-by-step explanation:

My approach was to draw out the probabilities, since we have 3 children, and we are looking for 2 boys and 1 girl, the probabilities can be Boy-Boy-Girl, Boy-Girl-Boy, and Girl-Boy-Boy. So a 2/3 chance if you think about it, your answer 2/3 can't be correct. If we assume that boys and girls are born with equal probability, then the probability to have two girls (and one boy) should be the same as the probability to have two boys and one girl. So you would have two cases with probability 2/3, giving an impossible 4/3 probability for both cases. Also, your list "Boy-Boy-Girl, Boy-Girl-Boy, and Girl-Boy-Boy" seems strange. All of those are 2 boys and 1 girl, so based on that list, you should get a 100 percent chance. But what about Boy-Girl-Girl, or Girl-Girl-Girl? You get 2/3 if you assume that adjacencies in the (ordered) list are important, i.e., "2 boys and a girl" means that the girl was not born between the boys.

5 0
1 year ago
write the condition to be satisfied by q so that a rational number p/q has a terminating decimal expansion​
hjlf
For a rational number to have a terminating decimal expansion
q should be in the form 5^m and 2^n or both. If q is not in the form of either then it is a non terminating recurring decimal expansion
6 0
3 years ago
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