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alexgriva [62]
3 years ago
7

NEED HELP ON MATH QUESTIONS

Mathematics
1 answer:
Masja [62]3 years ago
5 0

Answer:3

Step-by-step explanation:fvfvtbtbt

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3 years ago
HEEELP
Drupady [299]

Answer: (c)

Step-by-step explanation:

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f(x)=\dfrac{1}{x-3}\\\\g(x)=\sqrt{x+5}

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To get f\left(g(x)\right), replace x in f(x) by g(x)\ \text{i.e. by}\ \sqrt{x+5}

\Rightarrow f\left(g(x)\right)=\dfrac{1}{\sqrt{x+5}-3}\\\\\text{Denominator must not be equal to 0}\\\\\therefore \sqrt{x+5}-3\neq0\\\Rightarrow \sqrt{x+5}\neq 3\\\Rightarrow x+5\neq 9\\\Rightarrow x\neq 4\quad \ldots(ii)

Using (i) and (ii)  it can be concluded that the domain of f\left(g(x)\right) is all real numbers except 0.

Therefore, its domain is given by

x\in [-5,4)\cup (4,\infty)

Option (c) is correct.

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I hope I helped but I honestly have no idea if I did. Anyway sorry if I didn't. Good luck.
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