The answer to the first one is a
Answer:
Null Hypothesis: H_0: \mu_A =\mu _B or \mu_A -\mu _B=0
Alternate Hypothesis: H_1: \mu_A >\mu _B or \mu_A -\mu _B>0
Here to test Fertilizer A height is greater than Fertilizer B
Two Sample T Test:
t=\frac{X_1-X_2}{\sqrt{S_p^2(1/n_1+1/n_2)}}
Where S_p^2=\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2}
S_p^2=\frac{(14)0.25^2+(12)0.2^2}{15+13-2}= 0.0521154
t=\frac{12.92-12.63}{\sqrt{0.0521154(1/15+1/13)}}= 3.3524
P value for Test Statistic of P(3.3524,26) = 0.0012
df = n1+n2-2 = 26
Critical value of P : t_{0.025,26}=2.05553
We can conclude that Test statistic is significant. Sufficient evidence to prove that we can Reject Null hypothesis and can say Fertilizer A is greater than Fertilizer B.
Percent literally means per one-hundred so:
365(p/100)=146 multiply both sides by 100
365p=14600 divide both sides by 365
p=40%
Answer:
$3.42
Step-by-step explanation:
Meters of material required = 1.2 meters
Cost per meter of material = $0.85
Direct labor hours = 0.1
Cost of direct labor per hour = $15
Overhead rate = $9 per direct labor hour
Standard cost per unit of product :
(Direct material cost per unit + direct labor cost per unit + overhead cost per unit)
Direct material cost per unit :
Material needed × cost per meter = (1.2 × $0.85) = $1.02
Direct labor cost per unit :
Direct labor hour × cost per hour = ( 0.1 × $15) = $1.5
Overhead cost:
0.1 * $9 = $0.9
Standard cost :
($1.02 + $1.5 + $0.9) = $3.42
