Answer:
0.999999 ≈ 1
Explanation:
In a population ( N ) there is the presence of 2N alleles in the population also chance of fixation can be expressed as ; 1/ 2N
Therefore the probability that the mutation will be lost due to genetic drift
= 2N - 1 / 2N ---- ( 1 )
given that ; N = 100,000
back to equation 1
P ( losing mutation due to genetic drift ) = ((2*100,000) - 1 )) / ( 2* 100,000 )
= ( 200,000 - 1 ) / 200,000
= 0.999999 ≈ 1
I don’t think there is a limit in science because we didn’t discover even half of the ocean.
Answer:
3/4
Explanation:
If we assume simple dominance and independent assortment for each trait, we can use Mendel's Law of Segregation to predict the phenotypic proportions in the offspring of the parental cross AABBCc x AabbCc.
<h3><u>Gene A</u></h3>
AA x Aa
- F1 genotypes: 1/2 AA, 1/2 Aa
- F1 phenotypes: all A
<h3 /><h3><u>Gene B</u></h3>
BB x bb
- F1 genotypes: 1 Bb
- F1 phenotypes: all B
<h3 /><h3><u>Gene C</u></h3>
Cc x Cc
- F1 genotypes: 1/4 CC, 2/4 Cc, 1/4 cc
- F1 phenotypes: 3/4 C, 1/4 cc
We want to know the proportion of progeny with all dominant phenotype (A_B_C_). Since the genes are independent, we can multiply the probabilities of each gene to obtain the overall probability of having a ABC progeny:
<h3>1 A_ x 1 B_ x 3/4 C_ = 3/4 A_B_C_</h3>
