I need it done asapp

Andrei [34K]

K added to 10 gives you 4 times the value of K.

If you wanted to solve the expression:

Subtract both sides of the expression, right hand side(10+k) and left hand side(4K), by -k as you want to get rid of the variable to get simply 10 on the LHS.
10+k -k = 4k -k

If we want to subtract k from k then we get 0, and if we want to subtract k from 4k we get 3k. For the sake of simplicity think of k as an object saying if I subtract object A from object A I get zero, and so forth.

We are left with the expression:
10 = 3k
We divide both sides by 3 as to get rid of it from the RHS.
We get a solution 10/3 = k

8 0

3 years ago

I need help Quick!! 42-46 Thank you!! :)

sergiy2304 [10]

Answer:

4

Step-by-step explanation:

3 0

3 years ago

The port of South Louisiana, located along 54 miles of the Mississippi River between New Orleans and Baton Rouge, is the largest

jeka94

Answer:

(a) The probability that the port handles less than 5 million tons of cargo per week is 0.7291.

(b) The probability that the port handles 3 or more million tons of cargo per week is 0.9664.

(c) The probability that the port handles between 3 million and 4 million tons of cargo per week is 0.2373.

(d) The number of tons of cargo per week that will require the port to extend its operating hours is 5.35 million tons.

Step-by-step explanation:

Let X = amount of cargo the port handles per week.

The random variable X is Normally distributed with parameters,

μ = 4.5 million

σ = 0.82 million

(a)

Compute the probability that the port handles less than 5 million tons of cargo per week as follows:

$P(X$

*Use a z-table for the probability.

Thus, the probability that the port handles less than 5 million tons of cargo per week is 0.7291.

(b)

Compute the probability that the port handles 3 or more million tons of cargo per week as follows:

$P(X\geq 3)=P(\frac{X-\mu}{\sigma}\geq \frac{3-4.5}{0.82})\\=P(Z>-1.83)\\=P(Z$

*Use a z-table for the probability.

Thus, the probability that the port handles 3 or more million tons of cargo per week is 0.9664.

(c)

Compute the probability that the port handles between 3 million and 4 million tons of cargo per week as follows:

$P(3$

Thus, the probability that the port handles between 3 million and 4 million tons of cargo per week is 0.2373.

(d)

It is provided that P (X < x) = 0.85.

Then, P (Z < z) = 0.85.

The value of z for this probability is:

z = 1.04.

Compute the value of x as follows:

$z=\frac{x-\mu}{\sigma}\\1.04=\frac{x-4.5}{0.82}\\x=4.5-+1.04\times 0.82)\\x=5.3528\approx5.35$

Thus, the number of tons of cargo per week that will require the port to extend its operating hours is 5.35 million tons.

5 0

4 years ago

The following is an incorrect flowchart proving that point L, lying on line LM which is a perpendicular bisector of segment JK,

klio [65]

Answer:

B

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Dilation of a line by a scale factor 1/3 centered at the point (4,2)

Fiesta28 [93]

Answer:

(4/3,2/3) will the point on the line after dilation

Step-by-step explanation:

Dilation is a transformation in which every point on line is dilated or multiplied away by the scale factor. This means, that dilation either enlarges the figure or reduces it in size.

So that means, if a point A(1,1) lies on a line and this line is dilated by a factor 2. Then, the new line will be passing through point

A(1,1) ---> A'(2*1,2*1) = A'(2,2)

Given: point on line (4,2) and scale factor 1/3

Result: The point is transformed or dilated by factor 1/3

B(4,2) --> B'(4/3,2/3)

3 0

4 years ago