Question:
At noon a tank contains 6 cm of water after several hours it contains 3 cm of water what is the percent decrease of water in the tank
Answer:
The percent Decrease of water in the tank is 50%
Step-by-step explanation:
Given:
Initial amount of water in the tank at the noon = 6 cm
amount of water remained in water after several hours = 3 cm
To Find:
The percent decrease =?
Solution:
The percent decrease in the tank
=>
Substituting the values
=>
=>
=>
=> 50
Answer:
26
Step-by-step explanation:
21 + 2=22
2+2=4
22+4=26
Professor Dan Healy, one of my Engineering instructors back in prehistoric times, had a favorite way of showing us how to do this kind of problem ... I mean the kind that's incredibly easy, but your own fear gets in the way and convinces you that you can't handle it. Here is Prof. Healy's method.
For a few moments, call the square root of 5 by the name "cow".
cow - x = 4 . Solve this equation for 'x' :
Add 'x' to each side of the equation: cow = 4 + x
Subtract 4 from each side: cow - 4 = x
Now, we can put the real value back in place of 'cow' : <u>√5 - 4 = x</u>
That right there is a perfect solution. But If you absolutely need to
know the number, then grab your calculator:
√5 = 2.2361 (rounded)
x = √5 - 4 = 2.2361 - 4 = <u>-1.7639</u> (rounded)
