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zvonat [6]
3 years ago
5

If a point is randomly selected from the area under the curve, what is the probability that it will be in the black region?

Mathematics
1 answer:
ozzi3 years ago
4 0

Answer:

A) 0.5

Step-by-step explanation:

The probability between 0 and 3 is 0.49865

The probability of 0 or less (≤ 0) is 0.50000

Took the test on USA Test prep

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Find the value of z such that the area between -z and z is 85%
Marta_Voda [28]

We want the integral of the standard normal from -z to z to be 0.85.  Let's look at some standard normal tables and pick the right one.

It's easy to find the Erf one, which is the integral of the unit normal from 0 to z.  That will be exactly half of the integral from -z to z.  So we look for the z value corresponding to a probability of 0.425 in that table and find

z = 1.44

Answer: 1.44

[figure from Wikipedia]

8 0
4 years ago
Mr. Fields ordered 3 tons of gravel for driveway at a factory how many pounds of gravel did he order
azamat
6000 pounds because 1 ton is 2000 pounds so you times 2000 by 3 and get 6000
6 0
3 years ago
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2(5x + 4) = 8<br> 10x + 8 = 8<br> –[?] [ ]<br> -
umka21 [38]

Answer:

Step-by-step explanation:

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5 0
3 years ago
The proportion of values of X between -3 and 8, if ∼(5,4.2)
mash [69]

If I'm understanding the question correctly, you're saying that <em>X</em> is a random variable following a normal distribution with mean 5 and standard deviation 4.2, and you want to find the proportion of the distribution that lies in the interval (-3, 8). In other words, the probability

P(-3 < <em>X</em> < 8)

Transform <em>X</em> to <em>Z</em>, which follows the standard normal distribution with mean 0 and standard deviation 1, using the rule

<em>X</em> = <em>µ</em> + <em>σZ</em>   ==>   <em>Z</em> = (<em>X</em> - <em>µ</em>)/<em>σ</em>

where <em>µ</em> and <em>σ</em> are the mean and standard devation of <em>X</em>, respectively.

We have

P(-3 < <em>X</em> < 8) = P((-3 - 5)/4.2 < (<em>X</em> - 5)/4.2 < (8 - 5)/4.2)

… ≈ P(-1.904 < <em>Z</em> < 0.714)

… ≈ P(<em>Z</em> < 0.714) - P(<em>Z</em> < -1.904)

… ≈ 0.762 - 0.028 ≈ 0.734

3 0
3 years ago
John wants to buy a DVD player. The price is $100, and the sales tax is 5 percent. Store A is offering a 10 percent discount and
exis [7]

Answer:

Price of DVD at Store A = $ 94.5

Price of DVD at Store B = $ 95

Step-by-step explanation:

Given that

Price of DVD player = $ 100

Sales Tax = 5%

Now, lets calculate price of of DVD player at store A

The price of DVD player at store A after 10% discount = 100 - 10% of 100

The price of DVD player at store A after 10% discount= 100 - 0.1x100

The price of DVD player at store A after 10% discount= 100 - 10 = $90

Price of DVD player at store A after sales tax = 90 + 5% of 90

Price of DVD player at store A after sales tax = 90 + 0.05x90

Price of DVD player at store A after sales tax = 90 + 4.5

Price of DVD player at store A after sales tax = $94.5

Now, lets calculate price of of DVD player at store B.

The price of DVD player at store B= 100

Price of DVD player at store B after sales tax = 100 + 5% of 100

Price of DVD player at store B after sales tax = 100 + 0.05x100

Price of DVD player at store B after sales tax = 100 + 5

Price of DVD player at store B after sales tax = $ 105

Price of DVD player at store B $10 rebate = 105 - 10

Price of DVD player at store B $10 rebate = $95

4 0
3 years ago
Read 2 more answers
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