Area of a trapezoid is A=height over 2 B1 +B2, so 10+10=20, then 20(8)=160, 160/2=80. Answer is b.
Answer:
The minimum cost is $9,105
Step-by-step explanation:
<em>To find the minimum cost differentiate the equation of the cost and equate the answer by 0 to find the value of x which gives the minimum cost, then substitute the value of x in the equation of the cost to find it</em>
∵ C(x) = 0.5x² - 130x + 17,555
- Differentiate it with respect to x
∴ C'(x) = (0.5)(2)x - 130(1) + 0
∴ C'(x) = x - 130
Equate C' by 0 to find x
∵ x - 130 = 0
- Add 130 to both sides
∴ x = 130
∴ The minimum cost is at x = 130
Substitute the value of x in C(x) to find the minimum unit cost
∵ C(130) = 0.5(130)² - 130(130) + 17,555
∴ C(130) = 9,105
∵ C(130) is the minimum cost
∴ The minimum cost is $9,105
2 1/5x * 1 7/10 y * 4 3/5 x 1 7/10 (* 7 4/50)
Finds the answer
10 6/50x * 7 41/50y (* 7/4/50) = 56
79 13/100 (* 7 4/50) = 56
560 = 56 (10x)
x = 5 6/10
7 (y) = 56 (7y)
8 = 56/7 (y)
y = 8
x = 5 6/10
6/10 of 560 = 336
336/60 = x
336/60 = 5 6/10
The answer is 3214
3 is equivelant to 0.74
2 is equivelant to 0.88...
1 is equivelant to 7
4 is equivelant to 8
