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Y_Kistochka [10]
2 years ago
5

B+10+15 What’s the answer

Mathematics
2 answers:
irina [24]2 years ago
8 0
I think the answer is B+25
avanturin [10]2 years ago
7 0

Answer:

25b?

Step-by-step explanation:

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3 years ago
Which inequality is true when the value of R is 18? I'ma shower the answers i can choose in the picture ​
musickatia [10]

Answer:

See below:

Step-by-step explanation:

Hello! We can check to see if the inequality is true by replacing r with 18 as we have been told to find them in which 18 as r makes the equation true.

So our equations to test for are:

-r-3>-6\\-r+3

We can input 18 as r and then we see the following are correct:

1. No, as a -21 is not greater than -6

2. Yes, as -15 is less than 6.

3. No, as 21 is not greater than 6

4. No, as -15 is not greater than 6.

Cheers!

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3 years ago
What rule is represented by the table?
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5 0
2 years ago
Gradien garis -3x -2y = 7 adalah
Anuta_ua [19.1K]
Yo my bro the answer is 7621
3 0
2 years ago
Read 2 more answers
A jumbo crayon is composed of a cylinder with a conical tip. The cylinder is 12 cm tall with a radius of 1.5 cm, and the cone ha
s2008m [1.1K]

Answer:

Part 1) The  lateral area of the cone is LA=2\pi\ cm^{2}

Part 2) The lateral surface area of the cylinder is LA=36\pi\ cm^{2}

Part 3) The surface area of the crayon is SA=41.50\pi\ cm^{2}

Step-by-step explanation:

Part 1) Find the  lateral area of the cone  

The lateral area of the cone is equal to

LA=\pi rl

we have

r=1\ cm

l=2\ cm

substitute

LA=\pi (1)(2)

LA=2\pi\ cm^{2}

Part 2) Find the lateral surface area of the cylinder

The lateral area of the cylinder is equal to

LA=2\pi rh

we have

r=1.5\ cm

h=12\ cm

substitute

LA=2\pi (1.5)(12)

LA=36\pi\ cm^{2}

Part 3) Find the surface area of the crayon

The surface area of the crayon is equal to the lateral area of the cone, plus the lateral area of the cylinder, plus the top area of the cylinder plus the bottom base of the crayon

<em>Find the area of the bottom base of the crayon</em>

A=\pi[r2^{2}-r1^{2}]

where

r2 is the radius of the cylinder

r1 is the radius of the cone

substitute

A=\pi[1.5^{2}-1^{2}]

A=1.25\pi\ cm^{2}

<em>Find the area of the top base of the cylinder</em>

A=\pi(1.5)^{2}=2.25\pi\ cm^{2}

<em>Find the surface area</em>

SA=2\pi+36\pi+2.25\pi+1.25\pi=41.50\pi\ cm^{2}

8 0
3 years ago
Read 2 more answers
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