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statuscvo [17]
3 years ago
5

An elevator travels 310 feet in 10 seconds at that speed how far can this elevator travel

Mathematics
1 answer:
frez [133]3 years ago
6 0

Answer:

1,860 per minute and 111,600 per hour

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Find the area of this shape<br> giving brainliest please help
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ANSWER: ⇒ 366.19cm²

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2 years ago
Which ratio expresses the scale used to create this drawing? The school has dimensions of 18 feet by 18 feet.
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Answer A 1 square/2 feet=9 squares/18 feet
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Read 2 more answers
The quadratic function y = –10x2 + 160x – 430 models a store’s daily profit (y) for selling a T-shirt priced at x dollars. What
asambeis [7]

Answer:

x = 4 or x = 12

Step-by-step explanation:

Given:

y = -10x² + 160x - 430

When y = $50

50 = -10x² + 160x - 430

50 + 430 = -10x² + 160x

480 = -10x² + 160x

-10x² + 160x - 480 = 0

Divide through by -10

x² - 16x + 48 = 0

Solve the quadratic equation using factorization method

+48 = -12 × -4

-16 = -12 -4

Therefore,

-12 and -4 are both factors

x² - 16x + 48 = 0

(x - 4 )(x - 12 ) = 0

x - 4 = 0

x = 4

OR

x - 12 = 0

x = 12

6 0
3 years ago
Helppppppppp but no link
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3 years ago
Calculate the average travel time for each distance, and then use the results to calculate. A 6-column table with 3 rows in the
BigorU [14]

The average travel time is simply the mean travel time between the given points

  • The average time that it takes for the car to travel the first 0.25m is 2.23s.
  • The average time to travel just between 0.25m and 0.50m is 0.9s.
  • Given the time taken to travel the second 0.25 m section, the velocity would be 0.28m/s.

<u>(a) The average time to travel the first 0.25m</u>

The time travel in the first 0.25m are: 2.24s, 2.21s and 2.23s.

So, the average time to travel is:

Time = \frac{2.24s + 2.21s + 2.23s}{3}

Time = \frac{6.68s}{3}

Time = 2.23s

<u>(b) The average time to travel just between 0.25m and 0.50m</u>

The time travel in the 0.50m are: 3.16s, 3.08s and 3.15s.

So, the average time to travel this distance is:

Time = \frac{3.16s + 3.08s + 3.15s}{3}

Time = \frac{9.39s}{3}

Time = 3.13s

The average time to travel between both distance is the difference between the average time of each distance.

So, we have:

Average = 3.13s - 2.23s

Average = 0.9s

<u>(c) The velocity in the second 0.25m section</u>

The distance and time are:

Distance = 0.25m

Time = 0.9s

So, the velocity is:

Velocity = \frac{Distance}{Time}

This gives

Velocity = \frac{0.25m}{0.9s}

Velocity = 0.28m/s

Read more about distance, velocity and time at:

brainly.com/question/4931057

6 0
3 years ago
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