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frutty [35]
2 years ago
12

How can you make your answer (41-13i)/(25) into a+bi form?

Mathematics
1 answer:
KengaRu [80]2 years ago
5 0

Hello, do you know that for any a, b and c real numbers with c different from 0 the following is correct?

\dfrac{a+b}{c}=\dfrac{a}{c}+\dfrac{b}{c}

Then,

\dfrac{41-13i}{25}=\dfrac{41}{25}-\dfrac{13}{25}i

So,

a=\dfrac{41}{25}\\\\b=\dfrac{-13}{25}

Thank you.

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Can somebody help me please?
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3 years ago
The roots of a quadratic equation ax2+bx+c=0 are 3+sqrt2 and 3−sqrt2. Find the values of b and c assuming that a=1.
slamgirl [31]

Answer:

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Step-by-step explanation:

we know that

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y=a(x-x_1)(x-x_2)

where

a is a coefficient of the leading term

x_1 and x_2 are the roots

we have

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substitute

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therefore

b=-6\\c=7

7 0
2 years ago
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