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2 years ago

Help me please it due nowwwwwww

Mathematics

2 answers:

Natasha2012 [34]2 years ago

7 0

B is the correct answer because if u look on a graph/chart you can find that number

igomit [66]2 years ago

4 0

Answer:2nd one

Step-by-step explanation:

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A North Face Jacket costs $65. It is on sale for 20% off. What is the amount of discount?

sineoko [7]

The answer should be $13 !! hope that helps

5 0

2 years ago

32+44 distributive property

n200080 [17]

Answer: 76

Step-by-step explanation:

30 + 40 = 70

4 + 2 = 6

70 + 6 = 76

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2 years ago

Suppose Josh drives the 45 miles from Appleton to Berwyn at the constant speed of 30 miles per hour. On the return trip, he driv

Bas_tet [7]

Avarage speed is (60+30)/2 = 45 miles per hour

bot is the same , Do not think so it is a right question.

8 0

2 years ago

A solid is formed by adjoining two hemispheres to the ends of a right circular cylinder. An industrial tank of this shape must h

mestny [16]

Answer:

Radius =6.518 feet

Height = 26.074 feet

Step-by-step explanation:

The Volume of the Solid formed = Volume of the two Hemisphere + Volume of the Cylinder

Volume of a Hemisphere $=\frac{2}{3}\pi r^3$

Volume of a Cylinder $=\pi r^2 h$

Therefore:

The Volume of the Solid formed

$=2(\frac{2}{3}\pi r^3)+\pi r^2 h\\\frac{4}{3}\pi r^3+\pi r^2 h=4640\\\pi r^2(\frac{4r}{3}+ h)=4640\\\frac{4r}{3}+ h =\frac{4640}{\pi r^2} \\h=\frac{4640}{\pi r^2}-\frac{4r}{3}$

Area of the Hemisphere = $2\pi r^2$

Curved Surface Area of the Cylinder = $2\pi rh$

Total Surface Area=

$2\pi r^2+2\pi r^2+2\pi rh\\=4\pi r^2+2\pi rh$

Cost of the Hemispherical Ends = 2 X Cost of the surface area of the sides.

Therefore total Cost, C

$=2(4\pi r^2)+2\pi rh\\C=8\pi r^2+2\pi rh$

Recall: $h=\frac{4640}{\pi r^2}-\frac{4r}{3}$

Therefore:

$C=8\pi r^2+2\pi r(\frac{4640}{\pi r^2}-\frac{4r}{3})\\C=8\pi r^2+\frac{9280}{r}-\frac{8\pi r^2}{3}\\C=\frac{9280}{r}+\frac{24\pi r^2-8\pi r^2}{3}\\C=\frac{9280}{r}+\frac{16\pi r^2}{3}\\C=\frac{27840+16\pi r^3}{3r}$

The minimum cost occurs at the point where the derivative equals zero.

$C^{'}=\frac{-27840+32\pi r^3}{3r^2}$

$When \:C^{'}=0$

$-27840+32\pi r^3=0\\27840=32\pi r^3\\r^3=27840 \div 32\pi=276.9296\\r=\sqrt[3]{276.9296} =6.518$

Recall:

$h=\frac{4640}{\pi r^2}-\frac{4r}{3}\\h=\frac{4640}{\pi*6.518^2}-\frac{4*6.518}{3}\\h=26.074 feet$

Therefore, the dimensions that will minimize the cost are:

Radius =6.518 feet

Height = 26.074 feet

5 0

2 years ago

Find the area and perimeter of the shaded region. Stuck on this one can someone help me

alekssr [168]

Answer:

perimeter-

perimeter outer rectangle = 2 (l+b)

=2×8+9

= 2×17

2×17 =34 cm sq.

perimeter of inner rectangle = 2 (l+b)

= 2×5+3

=2× 8

= 16 cm sq.

perimeter of shaded portion= 34 - 16

= 18 cm sq.

area-

area of inner rectangle =l×b

l×b = 3×5

3×5=15

15 cm sq.

area of outer rectangle =l×b

l×b= 9×8

9×8= 72

72 cm sq.

area of shaded portion = 72 -15 =57 cm sq.

hey there! In second method i have done first area of inner rectangle but you have to do first area of outer rectangle...

hope it helps you....

3 0

2 years ago

Read 2 more answers