So 3^X= 2 is an exponential equation. The inverse of an exponential in ln. so take ln of both sides to solve.

Another way is to change the exponential into a log equation
So that would be log with base 3 to the power of 2 equals x.

7 0

3 years ago

A quadrilateral has 4 right angles, 2 pairs of sides of equal length,2 pairs of opposite sides that are parallel. The pairs of o

tekilochka [14]

That is describing a rectangle! The only quadrilaterals with 4 right angles are squares and rectangles. Squares have equal sides but rectangles have one pair of parallel sides that is longer than the other. Hope this helps! If you get more than one answer and see it fit to do so, please mark me Brainliest Answer! Thank you!

6 0

3 years ago

Subtract 4.32 x 10^6 from 7.57 x 10^6. Show your work. Write your answer in index notation.

Schach [20]

Answer:

3.25 × 10^6

Step-by-step explanation:

7.57×10^6 - 4.32 × 10^6

(7.57 - 4.32) × 10^6

<u>3.25 × 10^6</u>

8 0

3 years ago

What is the true solution to the equation below? In e^in x + in e^in x^2 = 2 in 8

mariarad [96]

To solve the given equation, w need to review some rules:
$(1) \ ln \ e = 1 \\ 
(2) \ ln \ b^{a} = a*ln \ b \\
(3) \ ln \ a + ln \ b = ln \ (ab) \\
(4) \ ln \ a - ln \ b = ln \ \frac{a}{b} \\$

The given equation is :
$ln \ e^{ln \ x} + ln \ e^{ln \ x^{2}} = 2 \ ln \ 8$
$ln \ x * ln \ e + ln \ x^{2} * ln \ e = 2 \ ln \ 8$ ⇒⇒⇒⇒ rule (2)
$ln \ x + ln \ x^{2} = ln \ 8^{2}$ ⇒⇒⇒⇒ rule (1) and rule (2)

$ln \ ( x* x^{2} ) = ln \ 64$ ⇒⇒⇒⇒ rule (3)
removing the nature logarithm from both sides

$x^{3} = 64 = 4^{3}$
∴ x = 4

So, the correct answer is option (2) ⇒⇒⇒⇒ x = 4

5 0

3 years ago

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