Answer:
Student B is correct
Student A failed to distribute -4 and -6 when opening the brackets in the first step
Step-by-step explanation:
The solution Student A gave was:
2x - 4(3x + 6) = -6(2x + 1) - 4
2x - 12x + 6 = -12x + 1 - 4
-10x + 6 = -12x - 3
2x = -9
x = -4 _1 2 ( -4 1/2)
The solution Student B gave was:
2x - 4(3x + 6) = -6(2x + 1) - 4
2x - 12x - 24 = -12x - 6 - 4
-10x - 24 = -12x - 10
2x = 14
x = 7
Student B is correct.
Explanation of the error:
Student A failed to distribute -4 and -6 when opening the brackets in the first step.
That is,
2x - 4(3x + 6) = -6(2x + 1) - 4
To open this bracket, we will distribute, -4 and -6 so that we get
2x (-4 × 3x) + (-4 × +6) = (-6×2x) + (-6 × +1) - 4
Then we will get
2x -12x -24 = -12x -6 -4
Adding the like terms
-10x - 24 = -12x - 10
Collecting like terms
-10x + 12x = -10 + 24
∴ 2x = 14
x = 14 / 2
Hence,
x = 7
Answer:
C(0,6)
Step-by-step explanation:
1) find the length of the base of the triangle
AB = 7-3 = 4
2) find the the height of the triangle
A = (base x height)/2
A x 2 = base x height
height = (A x 2)/base
height = (12 x 2)/4 = 6
3) find the equation of the line that passes threw the points AB
the two points have the same y so the equation of the line is
y = 0
4) use the formula of the distance between a point and a line to find C
|ax+by+c|/√a^2 + b^2 = distance
x = 0
y = 6
C (0,6)
The answer b your welcome so much
