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3 years ago

I need help on this hw

Mathematics

2 answers:

s2008m [1.1K]3 years ago

8 0

3rd choice, because you would need to multiply positive 3 to get a positive 9 positive times a positive if positive. negative times a negative is a negative

Aneli [31]3 years ago

4 0

Answer:

chose the last choice sinse you have 8y in the top equation we multiply the bottom one by +2to have -4y×2=-8y so we can cancle them by adition of the two equaotins

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I need help with my math worksheet

Vsevolod [243]

Answer:

Below is a reference sheet.

8 0

3 years ago

In ΔHIJ, h = 40 cm, ∠J=20° and ∠H=93°. Find the length of j, to the nearest centimeter.

DaniilM [7]

Given:

In ΔHIJ, h = 40 cm, ∠J=20° and ∠H=93°.

To find:

The length of j, to the nearest centimeter.

Solution:

According to Law of sine,

$\dfrac{a}{\sin A}=\dfrac{b}{\sin B}=\dfrac{c}{\sin C}$

In ΔHIJ, using law of sine, we get

$\dfrac{j}{\sin J}=\dfrac{h}{\sin H}$

$\dfrac{j}{\sin (20^\circ)}=\dfrac{40}{\sin (93^\circ)}}$

$j=\dfrac{40\times \sin (20^\circ)}{\sin (93^\circ)}}$

On further simplification, we get

$j=\dfrac{40\times 0.34202}{0.99863}$

$j=\dfrac{13.6808}{0.99863}$

$j=13.69958$

Approximate the value to the nearest centimeter.

$j\approx 14$

Therefore, the length of j is 14 cm.

7 0

3 years ago

Can Someone Help with This Distributive Property Math Question : <br> 1. - ( 8x - 12 )

Strike441 [17]

Answer:

-8x+12

Step-by-step explanation:

1. You need to distribute the (-1) from outside the bracket onto all the terms in the bracket, which includes (8x) and (-12). If there is a minus outside the bracket and one minus in the bracket, the operation would be a plus and vice versa. If there is a minus outside the bracket and one plus in the bracket, the operation would be a minus and vice versa.

- (8x - 12) = (-1) × (8x) + (-1) × (-12)

= -8x + (+12)

= -8x + 12

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3 years ago

Torrance

Aneli [31]

Answer:ew fdsetewt gfrs rta4rwea grdghz 4eagr ehr eg rw gre yhrgeg 4rw gre gre hre

rgre gzre hre g

Step-by-step explanation:gr egr esgre gr gr esgre sgv trsg rd hgf jxtrshbtg hgf

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3 years ago

Keith ate 2/6 of candy bar. If there were 6 pieces total, what fraction of the candy bar is left?

IgorC [24]

If there were 6 pieces and Keith ate 2 of the pieces, then there would be 4 pieces left.
$\frac{4}{6}$
and when you reduce it it would be
$\frac{2}{3}$

5 0

3 years ago

Read 2 more answers