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Alex_Xolod [135]
2 years ago
10

Use the graph of the polynomial function to find the factored form of the

Mathematics
1 answer:
irga5000 [103]2 years ago
7 0

Answer:

A. (x - 3)(x + 3)

Step-by-step explanation:

From the graph the x-axis is crossed by the graph at different points which are;

x = 3  and x = -3

This means the solutions are : x = 3 and x =-3

The factors will form the following equation : (x - 3)(x + 3)

See attached

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2 will replace each x on the right

3•(2^3) - 4•(2^2) + 2 -1
3•8 - 4•4 + 1
24 - 16 + 1
8+1
9
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3 years ago
Prove each statement that is true and find a counterexample for each statement that is false. Assume all sets are subsets of a un
tekilochka [14]

Answer with Step-by-step explanation:

We are given that A, B and C are subsets of universal set U.

We have to prove that

A\cap (B-C)=(A\cap B)-(A\cap C)

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Therefore, x\in( A\cap B) but x\notin (A\cap C)

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Conversely , Let x\in(A\cap B) but x\notin(A\cap C)

Then x\in A and x\in B

When x\notin ( A\cap C) then x\notin C

Therefor,x\in A\cap (B-C)

Hence, the statement is true.

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2 years ago
Abdul earns $13.00 in interest each month for six months. How much interest will Abdul have earned at the end of six months?
ipn [44]

answer:

78

<em>-- please mark the brainliest and click the thanks button if correct :)</em>

<em></em>

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Read 2 more answers
Bar graph is also known as​
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Answer:

Step-by-step explanation:

BAR CHART

Hope this helps

plz mark as brainliest!!!!!!!

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3 years ago
How does the graph of f(x)=3lx+2l+4 relate to its parent function?
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\bf \qquad \qquad \qquad \qquad \textit{function transformations}&#10;\\ \quad \\\\&#10;&#10;\begin{array}{rllll} &#10;% left side templates&#10;f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}&#10;\\ \quad \\&#10;y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}&#10;\end{array}

\bf \begin{array}{llll}&#10;% right side info&#10;\bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\&#10;\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}&#10;\\\\&#10;\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\&#10;\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\&#10;\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\&#10;\end{array}

\bf \begin{array}{llll}&#10;&#10;&#10;\bullet \textit{ vertical shift by }{{  D}}\\&#10;\qquad if\ {{  D}}\textit{ is negative, downwards}\\\\&#10;\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\&#10;\bullet \textit{ period of }\frac{2\pi }{{{  B}}}&#10;\end{array}

now, with that template above in mind, let's see this one

\bf parent\implies f(x)=|x|&#10;\\\\\\&#10;\begin{array}{lllcclll}&#10;f(x)=&3|&1x&+2|&+4\\&#10;&\uparrow &\uparrow &\uparrow &\uparrow \\&#10;&A&B&C&D&#10;\end{array}


A=3, B=1,  shrunk by AB or 3 units, about 1/3
C=2,          horizontal shift by C/B or 2/1 or just 2, to the left
D=4,          vertical shift upwards of 4 units

check the picture below

7 0
3 years ago
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