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3 years ago

Find the largest three-digit number that can be written in the form 3^m + 2^n, where m and n are positive integers.

Mathematics

1 answer:

joja [24]3 years ago

8 0

Answer:

985

Step-by-step explanation:

$let\ m=6$

$3^{6}=729$ $999-729=270$

$2^{8}=256$ and $2^{9}=512$ which would be to big of a number.

$3^{6}+2^{8}=729+256=985$

Therefore the largest three-digit integer in this system is 985

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Suma divizorilor naturali ai numărului 15

xenn [34]

Divizorilor naturali ai numărului 15 es 3 y 5. Suma de 3 y 5 es 8.

3 0

4 years ago

Please help me with this

vlabodo [156]

Ulterior exterior angles:

50+2y =180

50+x+5=180 55+x=180

50-50+2y=180-50

2y/2=130/2

y=65

5 0

3 years ago

Am I finding the area of this wierd shape correctly if not what am I doing wrong?

saw5 [17]

Answer:

8 $ft^2$

Step-by-step explanation:

Sadly, you are doing this incorrectly.

The easiest way to find the area of this shape is to separate it into a square and a triangle.

This will leave you with a square with the dimentions 2x2 a triangle with a base of 4 and a height of 2.

The area of the square is 4 $ft^2$

Using the equation for the area of a triangle

$A=\frac{1}{2} bh$

We can plug in our 2 know values to get

$A=\frac{1}{2} (4)(2)\\A=4$

Now we can take the sum of the areas of these two shapes to get a total area of 8 $ft^2$

3 0

3 years ago

Alana saved $1,200.00 to buy a pool table, but decided instead to charge it to her credit card. If the credit card had an intere

MrRa [10]

Answer:

the answer is $47.70

Step-by-step explanation:

8 0

4 years ago

Find the area of the figure. A) 114 cm2 B) 350 cm2 C) 418 cm2 D) 447 cm2

NISA [10]

Square has 4 equal sides so it would be the same for all the corresponding sides.

area of square = $s*s$

= $19*19$

= $361cm^2$

area of triangle = $\frac{hb}{2}$

= $19*6$

= $114/2$

= $57cm^2$

total area = $57+361=418cm^2$

5 0

3 years ago

Read 2 more answers