Question

Find the largest three-digit number that can be written in the form 3^m + 2^n, where m and n are positive integers.

Answer 1

Answer:

985

Step-by-step explanation:

$let\ m=6$

$3^{6}=729$$999-729=270$

$2^{8}=256$ and $2^{9}=512$ which would be to big of a number.

$3^{6}+2^{8}=729+256=985$

Therefore the largest three-digit integer in this system is 985