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Mazyrski [523]
3 years ago
11

In the figure below, ray MP and MQ both intersect line LN. What is the measure of angle QMN?

Mathematics
2 answers:
adelina 88 [10]3 years ago
8 0

Answer:

C

Step-by-step explanation:

sveticcg [70]3 years ago
5 0

Answer:

answer is c correct me if im wrong

Step-by-step explanation:

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John, Sam & Rob were playing cards. John scored x points,Sam scored 3 fewer than John. Rob scored twice Sam's points. togeth
Lostsunrise [7]

Answer:  2x-6

Work Shown:

john = x

sam = x-3 since he scored 3 fewer than john

rob = 2*(sam) = 2(x-3) = 2*x-2*3 = 2x-6

7 0
2 years ago
The angle of elevation of the top of a tower from a point 100m away is 45 degrees. What is the height of the tower to the neares
vladimir2022 [97]

Answer:

SOHCAHTOA.

TOA=opposite/adjacent.

Tan45=100/h.

h tan45=100.

h×1=100.

h=100m

7 0
4 years ago
Read 2 more answers
Choose the model that represents the function
kirill [66]

Answer:

OPTION D

Step-by-step explanation:

We have to determine which option determines the function given above.

To determine the function, just substitute the values and compare LHS and RHS.

we have $ f(4) = 18 $

$ f(-2) = -12 $

$ f(0) = -2 $

$ f(-3) = -17 $

Here, $ x $ is the domain and $ f(x) $ is the co-doamin.

Therefore, $ x = \{4, -2, 0, -3\} $

Now, OPTION A: $ f(x) =  2x - 5 $

Substitute x = 4. We get f(x) = 3 $ \ne $ 18.

So, OPTION A is rejected.

Similarly, OPTION B: $ f(x) = 5x + 2 $

Substitute x = 4. We get f(4) = 22 $ \ne $18.

It is rejected as well.

Now, for OPTION C: $ f(x) = \frac{x}{2} - 5 $

Substitute x = 4. We get f(4) = -3 $ \ne $ 18.

So, OPTION C is also rejected.

OPTION D: $ f(x) =  5x - 2 $

Substitute x = 4. We get f(4) = 18.

Substitute the remaining points in domain as well. We notice that it exactly matches the given function. So, OPTION D is the answer.

8 0
3 years ago
Helpppppppppppppppppppppp
olga nikolaevna [1]
Slope = change in y/change in x.

-2-0/2-1
-2/1
-2

Final answer: -2
7 0
3 years ago
6 - 3 ²/⁵ =<br> What is 6 - 3 ²/⁵
Leya [2.2K]

~\hspace{7em}\textit{rational exponents} \\\\ a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} ~\hspace{10em} a^{-\frac{ n}{ m}} \implies \cfrac{1}{a^{\frac{ n}{ m}}} \implies \cfrac{1}{\sqrt[ m]{a^ n}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ 6-3^{\frac{2}{5}}\implies 6-\sqrt[5]{3^2}\implies 6-\sqrt[5]{9}~~\approx ~~4.8

3 0
3 years ago
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